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2 years ago

GEOMETRY!!!! CLICK ON THE PICTURE

Mathematics

1 answer:

Helga [31]2 years ago

7 0

Answer:

#1 - Two complementary angles with measures that have a sum of 90.

#2- angles with a common vertex and side.

#3 - two supplementary angles with measures that have a sum of 180.

#4 - the region of a plane inside an angle

#5 - the region of a plane outside an angle

#6 - an angle with a measure of anything less than 90 degrees.

#7 - an angle with a measure of anything greater than 90 degrees.

These all should be right :)

Lmk how I did!

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Please help me, thanks.

bixtya [17]

Your expression would be

$(3 {}^{9} - 4) - r$
because of the order of operations this expression is valid to the world problem

3 0

2 years ago

1/5 (4-3x) = 1/7 (3x - 4)<br><br> pls solve it pls pls

8_murik_8 [283]

Answer:

x=4/3

Step-by-step explanation:

In pic

(hope this helps can I pls have brainlist (crown)☺️)

4 0

2 years ago

Read 2 more answers

Can someone help me with my mid term click download document

kari74 [83]

Answer:

1.D 2.D 3.B 4.B 5.B 6.B 7.C 8.C 9. Tickets sold/money collected

10. Tickets sold 11. Money collected 12. The money collected is 2 times more than tickets sold. 13. 80 dollars 14. 6 hours 15. Go by 25 on the y-axis (25 on first line, 50 on second line, 75 on 3rd line) and match them up to your table.

P.S. I'm not sure about my responses. Go check to make sure I'm right on them.

Step-by-step explanation:

7 0

1 year ago

Could the lengths 6,8, and 15 represent the sides of a triangle?

kupik [55]

No, because the sum of two sides must be larger than the third.

3 0

2 years ago

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

2 years ago