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Dafna11 [192]
3 years ago
8

Identify the cross section shown. a. circle b. hexagon c. trapezoid d. triangle

Mathematics
1 answer:
zepelin [54]3 years ago
5 0

Answer:

d

Step-by-step explanation:

You might be interested in
james invested some money at 13% interest. James also invested $199 more than 3 times that amount at 12%. How much is invested a
Komok [63]

9514 1404 393

Answer:

  • $3138 at 13%
  • 9613 at 12%

Step-by-step explanation:

Let x represent the amount invested at 13%. Then (3x+199) is the amount invested at 12%. The total interest earned in 1 year is ...

  (13%)(x) +(12%)(3x+199) = 1561.50

  0.49x +23.88 = 1561.50 . . . . simplify

  0.49x = 1537.62 . . . . . . . . . . subtract 23.88

  x = 3138 . . . . . . . . . . . . . . . . divide by 0.49

  3x+199 = 9613

$3138 was invested at 13%; $9613 was invested at 12%.

8 0
2 years ago
What is the solution for y=4x−9
nignag [31]
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

x-intercept: (9/4,0)

y-intercept: (0,−9)
7 0
3 years ago
Homework: 7.1 hw
Scrat [10]

Answer:

a. $ 2,431.01 = 4 years

b. $ 4,584.04  = 17 years

c. 4.57 years = $ 2,499.57

d. 8.3 year = $ 2,998.48

e.  $ 2,431.01 = 4 years

Step-by-step explanation:

Compound Interest Equation

A = P(1 + r/n)nt

Where:

A = Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

R = Annual Nominal Interest Rate in percent

r = Annual Nominal Interest Rate as a decimal

r = R/100

t = Time Involved in years, 0.5 years is calculated as 6 months, etc.

n = number of compounding periods per unit t; at the END of each period

5 0
3 years ago
Estimate the value of 9.9 power of 2 x 1.79 <br> pls some one help me
dybincka [34]

Answer:

The correct answer is 175.4379

Step-by-step explanation:

(9.9)^2 • 1.79

=98.01 • 1.79

=175.4379

3 0
3 years ago
12 7/10 m + 4 6cm + 7m 85 cm​
Inessa [10]
That would be 5+6m+7=5m
7 0
3 years ago
Read 2 more answers
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