9514 1404 393
Answer:
Step-by-step explanation:
Let x represent the amount invested at 13%. Then (3x+199) is the amount invested at 12%. The total interest earned in 1 year is ...
(13%)(x) +(12%)(3x+199) = 1561.50
0.49x +23.88 = 1561.50 . . . . simplify
0.49x = 1537.62 . . . . . . . . . . subtract 23.88
x = 3138 . . . . . . . . . . . . . . . . divide by 0.49
3x+199 = 9613
$3138 was invested at 13%; $9613 was invested at 12%.
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
x-intercept: (9/4,0)
y-intercept: (0,−9)
Answer:
a. $ 2,431.01 = 4 years
b. $ 4,584.04 = 17 years
c. 4.57 years = $ 2,499.57
d. 8.3 year = $ 2,998.48
e. $ 2,431.01 = 4 years
Step-by-step explanation:
Compound Interest Equation
A = P(1 + r/n)nt
Where:
A = Accrued Amount (principal + interest)
P = Principal Amount
I = Interest Amount
R = Annual Nominal Interest Rate in percent
r = Annual Nominal Interest Rate as a decimal
r = R/100
t = Time Involved in years, 0.5 years is calculated as 6 months, etc.
n = number of compounding periods per unit t; at the END of each period
Answer:
The correct answer is 175.4379
Step-by-step explanation:
(9.9)^2 • 1.79
=98.01 • 1.79
=175.4379