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3 years ago

WILL GIVE BRAINLIEST AND A HELLA LOT OF POINTS

Mathematics

2 answers:

Sladkaya [172]3 years ago

8 0

Answer:

I will only do Q.1

1 a. Sequence X_ is going up by 20

1 b. 8=116 and 13=236

1 c. Sequence a_ is down up by 13

1 d. 12=39 and 15=0

Step-by-step explanation:

1 a.Sequence X_ is going up by 20

1 b. go from 56

6=56 +20=76

7=76 +20=96

8= 96+20=116

9=116+20=136

10=136+20=156

11=156+20=176

12=196+20=216

13=216+20=236

1 c. Sequence a_ is down up by 13

1 d. go from 78

10=78-13=65

11=65-13=52

12=52-13=39

13=39-13=26

14=26-13=13

15=13-13=0

Luden [163]3 years ago

5 0

Answer:I will only do Q.11 a. Sequence X_ is going up by 201 b. 8=116 and 13=2361 c. Sequence a_ is down up by 131 d. 12=39 and 15=0Step-by-step explanation:1 a.Sequence X_ is going up by 201 b. go from 566=56 +20=767=76 +20=968= 96+20=1169=116+20=13610=136+20=15611=156+20=17612=196+20=21613=216+20=2361 c. Sequence a_ is down up by 131 d. go from 7810=78-13=6511=65-13=5212=52-13=3913=39-13=2614=26-13=1315=13-13=0

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Answer:

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Step-by-step explanation:

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Cost of annual ticket paid by Patrick last year = £2,534

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Percentage increase in the cost of his train ticket

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Percentage increase = [(Current - Base) / Base]100

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1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

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$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

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$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

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Equation of line is

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Therefore, the required equation is $2x+y-4=0$ .

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