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elena-14-01-66 [18.8K]
3 years ago
12

ANSWER NOW HURRY

Mathematics
2 answers:
Annette [7]3 years ago
5 0
The answer is C because it’s twice as long
stiv31 [10]3 years ago
4 0

Answer:

B It is the same length.

Step-by-step explanation:

Due to transformations, If you both rotate and reflect a segment it will still remain the same...

R' and T' is created if you do either on a coordinate plane.

Working on it on paper:

Lets create a problem...

"Triangle XYZ is reflected across a coordinate grid what happens to the length and variables?"

Answer: It stays the same length and the variables turn into X' Y' Z'.

With this evidence its safe to say the correct choice is B.

Hope this answer helped you! I scrounge around Brainly to find people in my wake and assist them, don't be shy to give me <u><em>Brainliest answer!</em></u>

<u><em>-Snooky</em></u>

You might be interested in
(X^2+y^2+x)dx+xydy=0<br> Solve for general solution
aksik [14]

Check if the equation is exact, which happens for ODEs of the form

M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0

if \frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}.

We have

M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y

N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y

so the ODE is not quite exact, but we can find an integrating factor \mu(x,y) so that

\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0

<em>is</em> exact, which would require

\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}

\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}

Notice that

\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y

is independent of <em>x</em>, and dividing this by N(x,y)=xy gives an expression independent of <em>y</em>. If we assume \mu=\mu(x) is a function of <em>x</em> alone, then \frac{\partial\mu}{\partial y}=0, and the partial differential equation above gives

-\mu y=-xy\dfrac{\mathrm d\mu}{\mathrm dx}

which is separable and we can solve for \mu easily.

-\mu=-x\dfrac{\mathrm d\mu}{\mathrm dx}

\dfrac{\mathrm d\mu}\mu=\dfrac{\mathrm dx}x

\ln|\mu|=\ln|x|

\implies \mu=x

So, multiply the original ODE by <em>x</em> on both sides:

(x^3+xy^2+x^2)\,\mathrm dx+x^2y\,\mathrm dy=0

Now

\dfrac{\partial(x^3+xy^2+x^2)}{\partial y}=2xy

\dfrac{\partial(x^2y)}{\partial x}=2xy

so the modified ODE is exact.

Now we look for a solution of the form F(x,y)=C, with differential

\mathrm dF=\dfrac{\partial F}{\partial x}\,\mathrm dx+\dfrac{\partial F}{\partial y}\,\mathrm dy=0

The solution <em>F</em> satisfies

\dfrac{\partial F}{\partial x}=x^3+xy^2+x^2

\dfrac{\partial F}{\partial y}=x^2y

Integrating both sides of the first equation with respect to <em>x</em> gives

F(x,y)=\dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3+f(y)

Differentiating both sides with respect to <em>y</em> gives

\dfrac{\partial F}{\partial y}=x^2y+\dfrac{\mathrm df}{\mathrm dy}=x^2y

\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C

So the solution to the ODE is

F(x,y)=C\iff \dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3+C=C

\implies\boxed{\dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3=C}

5 0
3 years ago
I am having a conflict with my family what is 7-1×0+3÷3 = ?
ryzh [129]
Follow PEMDAS.

Parenthesis
Exponents
Multiplication & Division
Addition & Subtraction

Alright, do multiplication first, then division. Then, do subtraction then addition.

7-1*0+3/3= \\ 7-0+3/3= \\ 7 - 0 + 1= \\ 7 + 1 = 8 \\ 7-1*0+3/3 =8

Hope this helped!
6 0
3 years ago
What is the measure of the indicated angle?<br><br> 180°<br><br> 6°<br><br> 84°<br><br> 96°
sleet_krkn [62]

Answer:

84°

Step-by-step explanation:

since the opposite side looks identical to the first angle, the second would be the same degrees.

3 0
2 years ago
Read 2 more answers
Need asapppp !!!!!!!
alina1380 [7]
X=70, y=55

The triangle is an isosceles triangles. In an isosceles triangle, the base angles are congruent.

Then use the triangle angle sum theorem and set the equation to 180.

55+55+x=180
110+x=180
x=70

The angle with 55 degrees and the angle with the variable y are alternate angles. Meaning they are congruent.
5 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
GrogVix [38]

Answer:

<u>1. Type of function</u>: absolute value function

<u>2. The three transformations from the parent function f(x) = |x| are</u>:

  • Translation 3 units to the left
  • Vertical stretch with a scale factor of 2
  • Translation 5 units downward

Explanation:

<u>1. Type of function</u>

The parent function |x| is the absolute value function. It returns the positive value of the argument (x).

Thus the function f(x) = 2|x + 3| - 5 is also an absolute value function.

It returns the positive value of x + 3, then multiplyes it by 2, and finally subtract 5.

This is a piecewise function.

For the values of x ≥ - 3, the output is 2(x +3) - 5 = 2x + 6 - 5 = 2x + 1.

For the values of x < - 3, the output is 2 (-x - 3) - 5 = -2x - 6 - 5 = -2x - 11.

The vertex of this function is at x = - 3: 2 (- 3 + 3) - 5 = 2(0) - 5 = 0 - 5 = 5.

Thus the vertex is (-3, 5).

<u>2. Transformations from the parent function f(x) = |x|</u>.

When you know the parent function and the daughter function you can know the transformations done of the former to get the later by some simple rules.

a)<u> Translation in the horizontal direction</u>.

When you add a positive value to the argument the function is translated to the left.

Thus, when you add 3 to x, |x| becomes |x + 3| and it is a translation 3 units to the left.

b) <u>Vertical stretch</u>

When you multiply the argument by a constant, the function stretches vertically.

Thus, when you multiply |x + 3| by 2, to get 2|x + 3|, the function is vertically stretched by a scale factor of 2.

c) <u>Vertical translation</u>

When you subtract a constant value from the function, you translate it downward.

Thus, when you subtract 5 from 2|x + 3| - 5, you translate the function 5 units downward.

6 0
3 years ago
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