First you had to remove parenthesis first.
Multiply by the numbers.
Final answer 
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The tiles go in this order: 4,3,2,1
Hope this helps!
Answer:
Option D (r(t) = 3.50t +25
; r(8) = 53)
Step-by-step explanation:
The fixed cost to rent the kayak $25. This is the cost which remains fixed irrespective of the usage of the kayak. The variable cost of using the kayak is the cost which depends on the usage of the kayak. It is mentioned that the kayak is used for 4 hours and the company charges $3.5 for every half hour. The cost function is given by:
r(t) = 25 + 3.5t ; there r is the total cost of using the kayak and t is the number of half-hours the kayak is used.
4 hours means that there are 8 half-hours. Therefore, t=8. Put t=8 in r(t).
r(8) = 25 + 3.5*(8) = 25 + 28 = 53.
Therefore, Option D is the correct answer!!!
Well, 50 points total given, 25 points per user and 13 bonus for brainliest
anyway
1.
add them equations, the y's will cancel
x+2y=4
<span>3x-2y=4 +</span>
4x+0y=8
4x=8
divide by 4 both sides
x=2
sub back
x+2y=4
2+2y=4
minus 2
2y=2
divide 2
y=1
x=2
y=1
(x,y)
(2,1) is solution
2.
the solution is where they intersect
multiply 2nd equation by 2 and add to first
4x-14y=6
<span>-4x+14y=-6 +</span>
0x+0y=0
0=0
infinite solutions
that is because they are actually the same line
the solutions are (x,y) such that they satisfy -2x+7y=-3 or 4x-14y=6 (same equaiton)
infinite solutions
3.
multiply first equation by 2 and add to first
4x+2y=-6
<span>1x-2y=-4 +</span>
5x+0y=-10
5x=-10
divide by 5 both sides
x=-2
sub bac
x-2y=-4
-2-2y=-4
add 2
-2y=-2
divide by -2
y=1
x=-2
y=1
(x,y)
(-2,1)
4.
coincident means they are the same line
so
we see that we have to multiply 4 by 2 to get 8
multiply top equation by 2
8x+10y=16
8x+By=C
B=10 and C=16
5.
a. false, either 0, 1, or infinity solutions
change the word 'two' to 'one' or 'zero' or 'infinite', or change 'can' into 'can't'
b.false
'sometimes' to 'always'
c. true
d. false, change 'sometimes' to 'always'
EC
total cost=150
TC=childC+adultC
TC=3c+5a
150=3c+5a
40 tickets, c+a
40=c+a
the equations are
150=3c+5a and
40=c+a
eliminate
multiply 2nd equaton by -3 and ad to first one
150=3c+5a
<span>-120=-3c-3a +</span>
30=0c+2a
30=2a
divide by 2
15=a
sub back
40=c+a
40=c+15
minus 15
25=c
25 children tickets and 15 adult tickets were sold
ANSWERS:
1.
(2,1) is solution
2.
infinite solutions
3.
(-2,1)
4.
B=10 and C=16
5.
a. false,
change the word 'two' to 'one' or 'zero' or 'infinite', or change 'can' into 'can't'
b.false
'sometimes' to 'always'
c. true
d. false, change 'sometimes' to 'always'
EC
the equations are
150=3c+5a and
40=c+a
25 children tickets and 15 adult tickets were sold
