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kirill [66]
3 years ago
7

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions:

Mathematics
1 answer:
Sav [38]3 years ago
7 0

Answer:

:Part A) The graph in the attached figure (see the explanation)

Part B) The ordered pair is not included in the solution area for the system (see the explanation)

Step-by-step explanation:

Part A) we have

y ----> inequality A

The solution of the inequality A  is the shaded area below the dashed line y=4x-8

The slope of the dashed line is positive

The y-intercept of the dashed line is (0,-8)

The x-intercept of the dashed line is (2,0)

y\geq -\frac{5}{2}x+5 ----> inequality B

The solution of the inequality B  is the shaded area above the solid line y=-\frac{5}{2}x+5

The slope of the solid line is negative

The y-intercept of the solid line is (0,5)

The x-intercept of the solid line is (2,0)

The solution of the system of inequalities is the shaded area between the dashed line and the solid line

see the attached figure

Part B) is the point (5, -8) Included in the solution area for the system?

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Substitute the value of x=5, y=-8 in each inequality and then analyze the results

<em>Inequality A</em>

-8

-8 ----> is true

so

the ordered pair satisfy inequality A

<em>Inequality B</em>

-8\geq -\frac{5}{2}(5)+5

-8\geq -7.5 ---> is not true

so

the ordered pair not satisfy the inequality B

therefore

The ordered pair is not included in the solution area for the system

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Answer:

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Step-by-step explanation:

I will assume you mean 3^x in the function f(x)

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              =  3^x+ 10  - 2x + 4

              = 3^x -2x +14

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3 years ago
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So Kylie drank:
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6 0
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9514 1404 393

Answer:

  a) no

  b) yes

  c) yes

  d) no

Step-by-step explanation:

Angle LJM is complementary to KJL, so is ...

  angle LJM = 90° -42° = 48°

Angle NJP is marked as congruent to angle PJQ, so is also 48°.

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a) ∠KJL = 42° ≠ 48° = ∠LJM . . . . NO

b) ∠MJP = 46°+48° = 48° +46° = ∠PJR . . . . YES

c) ∠LJP = 48° +46° +48° = 48° +48° +46° = ∠NJR . . . . YES

d) ∠MJK = 90° ≠ 48° +46° = ∠PJR . . . . NO

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3 years ago
The vertex of the parabola below is at the point (1, -2). Which of the following
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Answer:

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Step-by-step explanation:

I graphed my answer on the graph below and it matches your graph.

4 0
3 years ago
Solve the following equations for x,
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sin²(<em>x</em>) = 3/4

sin(<em>x</em>) = ± √3/2

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<em>x</em> = <em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + 2<em>nπ</em>

where <em>n</em> is any integer. The general result follows from the fact that sin(<em>x</em>) is 2<em>π</em>-periodic.

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, the first family of solutions gives <em>x</em> = <em>π</em>/3 and <em>x</em> = 4<em>π</em>/3 for <em>n</em> = 0 and <em>n</em> = 1, respectively; the second family gives <em>x</em> = 2<em>π</em>/3 and <em>x</em> = 5<em>π</em>/3 for <em>n</em> = 1 and <em>n</em> = 2.

(ii) 4 cos²(<em>x</em>) + 2 cos(<em>x</em>) - 2 = 0

2 cos²(<em>x</em>) + cos(<em>x</em>) - 1 = 0

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2 cos(<em>x</em>) = 1   <u>or</u>   cos(<em>x</em>) = -1

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[<em>x</em> = <em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   <em>x</em> = 5<em>π</em>/3 + 2<em>nπ</em>]   <u>or</u>   <em>x</em> = <em>π</em> + 2<em>nπ</em>

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7 0
3 years ago
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