4 C3H6 + 6 NO --> 4 C3H3N + 6 H2O + N2
1 answer:
4 moles
Explanation:
Given parameters:
number of moles of reacting NO = 24moles
Equation of the reaction:
4C₃H₆ + 6NO ⇒ 4C₃H₃N + H₂O + N₂
Solution:
The moles is synonymous the quantity of matter that contains the avogadro's number of particles.
To solve this problem, we must ensure that the given equation is balanced by simply inspecting.
The equation is balanced by inspection.
From the balanced equation;
6 moles of NO reacted to produce 1 mole of nitrogen gas
24 moles of NO will therefore produce = 4 moles
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Answer:
0.0177 L of nitrogen will be produced
Explanation:
The decomposition reaction of sodium azide will be:
As per the balanced equation two moles of sodium azide will give three moles of nitrogen gas
The molecular weight of sodium azide = 65 g/mol
The mass of sodium azide used = 100 g
The moles of sodium azide used =
so 1.54 moles of sodium azide will give = mol
the volume will be calculated using ideal gas equation
PV=nRT
Where
P = Pressure = 1.00 atm
V = ?
n = moles = 2.31 mol
R = 0.0821 L atm / mol K
T = 25 °C = 298.15 K
Volume =