All categories

4 years ago

When should a lab coat, safety goggles, and gloves be worn in the laboratory?

2 answers:

8 0

I would say that you should wear a lab coat, safety goggles, and gloves when the teacher says so - not everything in a lab is dangerous, so there is no need to always wear these. But when the teacher says you should - then you should.

Genrish500 [490]4 years ago

5 0

I would say you should wear it in a lab when you are working with dangerous chemicals. not any chemical is dangerous. hope this helped! :)

You might be interested in

Which of the following are compounds? (Select all that apply.)<br> CO2<br> Cl2<br> Ne<br> NaCl

beks73 [17]

CO2 and NaCl are both compounds

8 0

3 years ago

Which property of waves is the distance between one point on a wave and that same point on the wave next to it?

mr Goodwill [35]

The answer is B, wavelength

4 0

3 years ago

Read 2 more answers

I am a little confused

Sonbull [250]

The answer is D. I did that and i got it right.

7 0

3 years ago

Read 2 more answers

Magnesium and oxygen balanced

11Alexandr11 [23.1K]

2Mg+ O₂= 2MgO
The charge of Mg is+2 and the charge of Oxygen is -2. 2 oxygen atoms will have a charge of -4 so the Mg atoms have to equal +4. A coefficient of 2 for the Mg atoms will balance it out

8 0

3 years ago

Using the molarity equation, calculate how many grams of salt you need in order to make 80ml of a 2M solution (MW = 58.44g/mole)

ollegr [7]

Answer:

9.35g

Explanation:

The molarity equation establishes that:

$\textrm{molarity}=\frac{\textrm{moles of solute}}{\textrm{liters of solution}}$

So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:

$\textrm{moles of solute}=\textrm{molarity}*\textrm{liters of solution}$

$\textrm{moles of solute}= 0.08 \textrm{ l} *2\textrm{ M} = 0.16 \textrm{ mol}$

The mathematical equation that establishes the relationship between molar weight, mass and moles is:

$\textrm{molar weight}= \frac{\textrm{mass}}{\textrm{moles}}$

$\textrm{MW}= \frac{\textrm{m}}{\textrm{n}}$

We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem:

$\textrm{m} = \textrm{MW * n}= 58.44\frac{\textrm{g}}{\textrm{mol}} * 0.16 \textrm{ mol} = 9.35 \textrm{ g}$

8 0

4 years ago