Answer:
1. Hydrogen will diffuse faster.
2. The ratio of diffusion of hydrogen gas to that of the unknown gas is 4 : 1
Explanation:
Let the rate of diffusion of hydrogen gas, H2 be R1
Let the molar mass of H2 be M1
Let the rate of diffusion of the unknown gas be R2.
Let the molar mass of the unknown gas be M2.
Molar mass of H2 (M1) = 2x1 =2g/mol
Molar mass of unknown gas (M2) = 16 times that of H2
= 16 x 2 = 32g/mol
1. Determination of the gas that will diffuse faster. This is illustrated below:
R1/R2 = √(M2/M1)
R1/R2 = √(32/2)
R1/R2 = √16
R1/R2 = 4
Cross multiply
R1 = 4R2
From the above calculations, we can see that the rate of diffusion H2 (R1) is four times the rate of diffusion of the unknown gas (R2).
Therefore, hydrogen will diffuse faster.
2. Again, from the calculations made above, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is given by;
R1/R2 = 4
Therefore, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is:
4 : 1
The answer will be because of the unequal sharing of electrons between the hydrogen and the oxygen atoms of a water molecule.
Hope this helps.
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Answer:
0.84kg of gatorade powder is needed.
Explanation:
From the question given above, we were told that the team manager mixes 0.6kg of gatorade powder with 5 gallons of water.
Now, to obtain the desired amount of the powder of gatorade needed for 7 gallons of water, we simply do the following:
If 0.6kg of gatorade powder required 5 gallons of water,
Then Xg of gatorade will require 7 gallons of water i.e
Xg of gatorade = (0.6 x 7)/5
Xg of gatorade = 0.84kg
Therefore, to maintain the same gatorade mixture, the team manager must mix 0.84kg of gatorade powder with the 7 gallons of water.
Answer:
The middle hydrogen is bonded to 2
elements.
Each hydrogen must be bonded to one element which is oxygen
Answer:
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- <u>b. See the description below</u>
Explanation:
<u><em>a. Volume of 0.400 M CuSO₄(aq) required for the preparation</em></u>
In dissolutions, since the number of moles of solute is constant, the equation is:
Substitute and solve for V₁
<u><em>b. Briefly describe the essential steps to most accurately prepare the 0.150 M CuSO₄(aq) from the 0.400 M CuSO₄(aq)</em></u>
You will use the stock solution, the funnel, the buret, and distilled water.
i) Using the funnel, fill in the buret with with 50 ml of the stock solution, i.e. the 100. ml of 0.400 M CuSO₄(aq) solution.
ii) Pour 37.5 ml of the stock solution from the burete into the volumetric flask.
iii) Carefully add disitlled water to the 37.5ml of the stock solution in the volumetric flask until the mark (50 ml) on the volumetric flask.
iv) Put the stopper and rotate the volumetric flask to homegenize the solution.
