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aliya0001 [1]
3 years ago
11

What is the area of the triangle?

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
The answer would be 24 square centimeter cause 8x3 =24
fomenos3 years ago
6 0

Answer:

D. 24 square centimeters

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29*47 in expanded algorithm
Tresset [83]

Hey there! :D

So for this problem, we would do 20+9 x 40 + 7 which equals 1,363.

Hope it helps! :D

7 0
3 years ago
Read 2 more answers
Mrs. Anderson bought 5 tickets to Six Flags, and a $16.50 parking pass. She spent a total of $132.75. If each ticket was the sam
Alexxandr [17]
The answer would be $23.25 per ticket. to find this answer, you first subtract the $16.50 parking pass fee from the total amount mrs. anderson spent. you then can proceed to divide that number by 5, the number of tickets she bought. this leaves you with the answer!
3 0
3 years ago
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Will give brainiest, need help
eimsori [14]

Answer:

f(6) = 53

Step-by-step explanation:

f(x) = 10x - 7

We want to find f(6)

To do so simply substitute 6 for x in the equation

Equation: 10x - 7

x = 6

f(6) = 10(6) - 7

multiply 10 and 6

f(6) = 60 - 7

subtract

f(6) = 53

8 0
3 years ago
Read 2 more answers
Consider a rabbit population​ P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa
maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$         .............(1)

where, B = aP = birth rate

            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
4 years ago
What is the perimeter?
Inessa [10]

Answer:

19.25 inches

Step-by-step explanation:

x^2 + 5^2 = 8^2= 64

25+ x^2 = 64

x^2 = 64-25= 39

x = 6.24

perimeter = 19.24

3 0
3 years ago
Read 2 more answers
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