Answer:
21x^2 + 20x + 4 = (3x + 2)(7x + 2).
Step-by-step explanation:
Given the expression is 21x² +20x +4
We can solve the equation as follows:-
21x² +20x +4 = 0
Then a = 21, b = 20, c =4.
Using Quadratic formula, x = ( -b ± √(b² -4ac) )/2a
x = ( -20 ± √(400 - 4*21*4) )/2*21
x = ( -20 ± √(400 - 336) )/42
x = ( -20 ± √(64) )/42
x = ( -20 ± 8 )/42
x = -28/42 or x = -12/42
x = -2/3 or x = -2/7
(x + 2/3) = 0 or (x + 2/7) = 0
Now the factored form can be written as follows:-
(x + 2/3)(x + 2/7) = 0
(3x+2)(7x+2) = 0
Hence, the factored form is 21x^2 + 20x + 4 = (3x+2)(7x+2).
