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3 years ago

Five-sixths of the distance from 1 to −13

Mathematics

1 answer:

Finger [1]3 years ago

8 0

The distance of 1 to -13 is 14.

Five sixths of this is (.8333*14), which equals 11.6667.

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B28%7D%7B54%7D%20%3D%20%5Cfrac%7B2x%2B8%7D%7B5x-4%7D" id="TexFormula1" title="\frac{2

tia_tia [17]

Step-by-step explanation:

step 1. what is the question? solve for x? okay.

step 2. 28/54 = (2x+ 8)/(5x - 4)

step 3. 28(5x - 4) = 54(2x + 8) (cross multiplication)

step 4. 14(5x - 4) = 27(2x + 8) (divide both sides by 2)

step 5. 70x - 56 = 54x + 216 (distributive property)

step 6. 16x = 272 (group x's and add 56 to both sides)

step 7. x = 17 (divide both sides by 16).

5 0

3 years ago

When completing the square on the equation c2 + 110 = 12, the resulting solution is: It

Delvig [45]

Answer:

$c=1$ and $c=-12$

Step-by-step explanation:

The correct equation is:

$c^2+11c=12$

To solve by completing the square method.

Solution:

We have:

$c^2+11c=12$

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

$c^2+2.\frac{11}{2}c=12$

$c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2=12$ [As $c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2$ ]

Adding both sides by $(\frac{11}{2})^2$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2$

$(c+\frac{11}{2})^2=12+\frac{121}{4}$

Taking LCD to add fraction.

$(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}$

$(c+\frac{11}{2})^2=\frac{169}{4}$

Taking square root both sides.

$\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}$

$c+\frac{11}{2}=\pm\frac{13}{2}$

Subtracting both sides by $\frac{11}{2}$ :

$c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}$

$c=\pm\frac{13}{2}-\frac{11}{2}$

So, we have:

$c=\frac{13}{2}-\frac{11}{2}$ and $c=-\frac{13}{2}-\frac{11}{2}$

$c=\frac{2}{2}$ and $c=\frac{-24}{2}$

$c=1$ and $c=-12$ (Answer)

6 0

4 years ago

For each of the values of h given, when x is increased from 1 to 1+h, work out:

borishaifa [10]

This exercise should show you that as h approaches zero you get the value of the derivative of x^2 at x=1.

the change in x^2) / h
h=1___
h=.1____
h=0.1_____
h=.001___

change in x^2 = (1+h)^2 - 1^2 = (1+h)^2 - 1

5 0

3 years ago

What is the ratio of dimes to pennies in a dollar

maw [93]

Well, there are 100 pennies in a dollar, and 10 dimes in a dollar. So, the ratio could be 10:100, or 1:10.

8 0

3 years ago

Read 2 more answers

Who can help me with this algebra thanks for your help guys.

hjlf

31. +
34. -
To figure out more, just solve the known problem, and then go over what the answer would be to the unknown one until you find the answer that makes it true.

6 0

3 years ago