Answer:
First, we need to find how far ahead Marshall was. Since he had been biking at 20 mph for one hour, he had gone 20 miles.
Next, we need to find how long it will take Brett to catch up to Marshall. In order to do this, we need to find how much faster Brett is going than Marshall. We do this by subtracting Marshall's speed from Brett's speed.
60 - 20 = 40. So, Brett is catching up to Marshall at 40 mph. Now, we figure out how long it will take for someone going 40 miles per hour to go 20 miles. We find this by dividing 40 miles per hour by 20. This is equal to 1/2 hour. So, it will take Brett 0.5 hours to catch up to Marshall. This is the same as A, so A is the correct answer.
We can check our answer by seeing how far Marshall and Brett will have gone. Marshall will have been biking for 1.5 hours, so we multiply 20 * 1.5 = 30. Marshall went 30 miles.
Brett drove for .5 hours at 60 mph, so he went 30 miles. Since Brett and Marshall went the same distance, our answer is correct.
Answer:
7/9
Step-by-step explanation:
If the chances of an outcome are 2/9, the odds against it can be found by subtracting that from 1.
1 - 2/9
= 7/9
So, the odds against that outcome are 7/9
Answer:move -5x to the right becomes 5x
Y=5X+2
When x =1 5(1)+2= 7 for Y
When X=2 5(2)+2= 12 for Y
When X =-1 5[-1)+2/ -3
Coordinates (1,7).(2,12)(-1,-3)
Step-by-step explanation:
Implicit defferentation
remember that dy/dx y= dy/dx
so
take derivitive of both sides
solve for
minus 2x both sides
divide both sides by 2y
when is the slope equal to
solve for
find where the circle and this line intersects
substitute
for y
times both sides by
sqrt both sides, take positive and negative roots
x=+/-10
sub back
the points are (10,-24) and (-10,24)
Answer:
<h3>1</h3>
Step-by-step explanation:
The nth term of an exponential sequence is expressed as ar^n-1
The nth term of a linear sequence is expressed as Tn = a + (n-1)d
a is the first term
r is the common ratio
d is the common difference
n is the number of terms
Let the three consecutive terms of an exponential sequence be a/r, a and ar
second term of a linear sequence = a +d
third term of a linear sequence = a + 2d
sixth term of a linear sequence = a + 5d
Now if the three consecutive terms of an exponential sequence are the second third and sixth terms of a linear sequence, this is expressed as;
a/r = a + d ..... 1
a = a + 2d ..... 2
ar = a+ 5d .... 3
From 2: a = a + 2d
a-a= 2d
0 = 2d
d = 0/2
d = 0
Substitute d = 0 into equation 1:
From 1: a/r = a + d
a/r = a+0
a/r = a
Cross multiply
a = ar
a/a = r
1 = r
Rearrange
r = 1
<em>Hence the common ratio of the exponential sequence is 1</em>
