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Masteriza [31]
3 years ago
5

What is the slope of the line that contains the points (-3, -2) and (4, -2)?

Mathematics
2 answers:
schepotkina [342]3 years ago
6 0
You have to use the formule: y2-y1/x2-x1
-2-(-2)/4-(-3)=0/7
Dovator [93]3 years ago
5 0

Answer:

slope of the line =0

Step-by-step explanation:

Let slope of the line be m given by

\frac{y2 - y1}{x2 - x1}  =  \frac{ - 2 - ( - 2)}{4 - ( - 3)}  =  \frac{ - 2 + 2}{4 + 3}  =  \frac{0}{7}  = 0

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7.5

Step-by-step explanation:

because 7.5 x 16 = 120

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Read 2 more answers
Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in
tatuchka [14]

Answer:

The equation representing how old Monique son is \mathbf{a = 2 + \dfrac{8}{21}(q-34)}

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

q(t) = \hat q \times t + q_o

where;

q_o = initial height of Monique's son

\hat q = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

\hat q = 2 \dfrac{5}{8} \ in/yr

\hat q =  \dfrac{21}{8} \ in/yr

Then; from the equation q(t) = \hat q \times t + q_o

34 = \dfrac{21}{8} \times 0 + q_o

q_o = 34\  inches

The height of the son as a function of the age can now be expressed as:

q(t) = \dfrac{21}{8} \times t + 34

Then:

Making t the subject;

q - 34 = \dfrac{21}{8} \times t

t = \dfrac{8}{21}(q-34)

and the age of the son  i.e. ( a (in years)) is:

a = 2 + t

So;

\mathbf{a = 2 + \dfrac{8}{21}(q-34)}

SO;

if q (growth rate) = 50 inches tall

Then;

\mathbf{a = 2 + \dfrac{8}{21}(50-34)}

\mathbf{a = 2 + \dfrac{8}{21}(16)}

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0
2 years ago
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