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3 years ago

What is the slope of the line that contains the points (-3, -2) and (4, -2)?

Mathematics

2 answers:

schepotkina [342]3 years ago

6 0

You have to use the formule: y2-y1/x2-x1
-2-(-2)/4-(-3)=0/7

Dovator [93]3 years ago

5 0

Answer:

slope of the line =0

Step-by-step explanation:

Let slope of the line be m given by

$\frac{y2 - y1}{x2 - x1} = \frac{ - 2 - ( - 2)}{4 - ( - 3)} = \frac{ - 2 + 2}{4 + 3} = \frac{0}{7} = 0$

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Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)

irina1246 [14]

Answer:

Maximize C = $9x + 7y$

$8x + 10y \leq 17$

$11x + 12y\leq 25$

and x ≥ 0, y ≥ 0

Plot the lines on graph

$8x + 10y \leq 17$

$11x + 12y\leq 25$

$x\geq 0$

$y\geq 0$

So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)

Substitute the points in Maximize C

At (0,1.7)

Maximize C = $9(0) + 7(1.7)$

Maximize C = $11.9$

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Maximize C = $9(2.125) + 7(0)$

Maximize C = $19.125$

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Maximize C = $9(0) + 7(0)$

Maximize C = $0$

So, Maximum value is attained at (2.125,0)

So, the optimal value of x is 2.125

The optimal value of y is 0

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