Answer:
i. The ratio of the areas of the two triangles is 5:8.
ii. The area of the larger triangle is 24 in².
Step-by-step explanation:
Let the area of the smaller triangle be represented by 
, and that of the larger triangle by 
.
Area of a triangle = 
x b x h
Where; b is its base and h the height.
Thus,
a. The ratio of the area of the two triangles is:
Area of smaller triangle = x b x h
= x 5 x h
= 
h
Area of the lager triangle = x b x h
= x 8 x h
= 4h
So that;
Ratio = 
= 
The ratio of the areas of the two triangles is 5:8.
b. If the area of the smaller triangle is 15 in², then the area of the larger triangle can be determined as;
=
=
5 = 15 x 8
= 120
= 
= 24
The area of the larger triangle is 24 in².
Answer: the answer is 224cm3
0.188 because the 5 in 0.1875 rounds up
9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.
where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
