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4 years ago

Question in image. Thanks!

Mathematics

1 answer:

boyakko [2]4 years ago

8 0

Answer:

B (i do also slightly lean towards C, but i'm pretty sure it would be B because it gives a specific measurement)

Step-by-step explanation:

If all angles that are either adjacent or opposite are supplementary, all angles must be 90°

If at all times adjacent sides are 5 inches, all sides are equal.

Knowing this, it has to be a square because all angles would be 90° and all sides would be equal.

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Joseph had started saving quarters,dimes,nickel and penny but is unable to give the

Sladkaya [172]

Answer:

$3.49

12 quarters,4 dimes,1 nickle, 4 pennies

Step-by-step explanation:

First remember that;

Quarter=25 pennies

Dime=10 pennies

Nickel =4 pennies

I cent =0.01$

Given the amount as $3.50

Assume you use 4 quarters, this means a whole dollar, so it will be;

1 dollar = 4quarters

3 dollars=?

cross multiply

3×4=12 quarters

The remaining $0.49

Here identify 40 cents, which is 40 pennies

But 10 pennies=1 dime

so 40 pennies=?

cross-multiply

(40×1)÷10=4 dimes

and a nickel for 4 pennies.

7 0

4 years ago

Simplify: 36.6 ÷ (12)

Svetllana [295]

Answer:

Hi! The answer to your question is $3.05$

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☆Brainliest is greatly appreciated!☆

<em>Hope this helps!!</em>

<em>- Brooklynn Deka</em>

4 0

3 years ago

Evaluate the expression. If necessary, round to the nearest hundredth. e^In5

Murrr4er [49]

$e^{\ln x}=x\\\\ e^{\ln 5}=5$

7 0

3 years ago

After increasing the price of an item by 20% the price was $300.00. What was the original price?

zavuch27 [327]

Answer:

240000

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the maximum height of the basketball when the player passes the ball to someone? Initially, the ball moves at a speed of

ZanzabumX [31]

Answer with explanation:

Since the motion of the ball is projectile motion we shall use the equations for projectile motion.

The maximum height achieved by the projectile is given by

$h_{max}=\frac{v_{o}^{2}sin^{2}(\theta )}{2g}$

Applying the values we get

$h_{max}=\frac{12^{2}\times sin^{2}(45)}{2\times 9.81}\\\\h_{max}=3.669m$

The range of the projectile is given by

$R=\frac{v_{o}^{2}sin(2\theta )}{2g}$

Applying values we get

$R=\frac{12^{2}\times sin(2\times 45 )}{2\times 9.81}\\\\R=7.339m$

thus the maximum horizontal distance reached by the ball equals 7.339 meters after which it bounces thus a person standing 8 meters away will not be able to catch it.

(The height of the players is not taken into account since no info is given about their height.)

3 0

4 years ago