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torisob [31]
3 years ago
8

How do you solve 2x+4=7

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0
2x+4=7  subtract 4 from both sides

2x=3  divide both sides by 2

x=3/2

x=1.5


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Adric has a rope 9 yards long. He cuts off 7 pieces of rope,
astraxan [27]

Answer:

0.75 x 7 = 5.25

9-5.25=3.75

3.75/0.38=

9.86

round down because the rope has to be full

9 is your answer

Step-by-step explanation:

5 0
3 years ago
Fill in the Blank: 10 quarts =<br> pints
givi [52]

Answer:

10 quarts = 20 pints.

Step-by-step explanation:

Hope my answer has helped you and if not I am sorry.

8 0
3 years ago
Read 2 more answers
Factorize:<br>3a^2 + 10a + 3​
sergey [27]

Answer: (3a + 1) (a + 3)

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the idea of factorization.

It is like "splitting" an expression into a multiplication of simpler expressions. Factoring is also the opposite of Expanding.

<u>Solve:</u>

Given = 3a² + 10a + 3

<em>STEP ONE: separate 3a² into two terms</em>

3a

a

<em>STEP TWO: separate 3 into two terms</em>

3

1

<em>STEP THREE: match the four terms in ways that when doing cross-multiplication, the result will give us 10a.</em>

3a     1

a       3

When cross multiply, 3a × 3 + 1 × a = 10a

<em>STEP FOUR: combine the expression horizontally to get the final factorized expression.</em>

3a  ⇒   1

a   ⇒    3

(3a + 1) (a + 3)

Hope this helps!! :)

Please let me know if you have any questions

7 0
3 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
The angle of elevation to the top of a water tower from point A on the ground is 19.9°. From point B, 50.0 feet closer to the to
zepelin [54]

Answer:

Answer in terms of a trigonometric function :

h = \frac{20tan(19.9)}{0.4-tan(19.9)}

Answer in figures

h = 190.5 feet

Step-by-step explanation:

Consider the sketch attached below to better understand the problem.

Let x be the distance between point B and the base of the water tower.

tan (19.9)=\frac{h}{50+x} ---------------equation 1\\

tan (21.8)=\frac{h}{x}----------------equation 2

From equation 2,

x =\frac{h}{tan21.8}=\frac{h}{0.4}

substituting the value of x into equation 1, we get

tan (19.9)=\frac{h}{50+(\frac{h}{0.4} )}

tan 19.9=h\times \frac{0.4}{20+h}

cross multiplying,

20\times tan(19.9) +htan(19.9)=0.4h

20tan(19.9)= h(0.4-tan(19.9))

h= \frac{20tan (19.9)}{0.4-tan (19.9)}

The height of the tower is h= \frac{20tan (19.9)}{0.4-tan (19.9)} in terms of the trig function "Tan"

The equation can simply be evaluated to get the answer in figures since the angles are given in the question

5 0
3 years ago
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