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dedylja [7]
2 years ago
9

24x²/5xy simplified fully

Mathematics
1 answer:
jarptica [38.1K]2 years ago
5 0

Step-by-step explanation:

exponents are subracted when divided

so next step is

24x/5y and this is the answer

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If the sales tax in a town is 5% and Amanda pays $10 in tax on her purchase what was the cost of the item?
Vikentia [17]

Answer:

$200

Step-by-step explanation:

If the tax is 5%, then she pays $5 for every $100. If she paid $10 in tax, her purchase was $200.

5 0
2 years ago
Look at this equation 3(x+1)=3x=? which number can be placed in the box *the question mark* that would create an equation that h
KATRIN_1 [288]
The answer to this is 0
8 0
3 years ago
2t-7-5t=11 what is the answer
Verizon [17]
<span>2t-7-5t=11

Start by combing like terms:

2-5t=-3t  

Now we have: 

-3t-7=11  

Add 7 to both sides

-3t=18

To isolate t we divide both sides by -3 

Final answer: 
t=-6 </span>
3 0
3 years ago
out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i
Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

80% passed in mathematics 75% passed in english

This means that P(A) = 0.8, P(B) = 0.75

Proportion who passed in both:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

Considering the values we have for this problem

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

0.6t = 3000

t = \frac{3000}{0.6}

t = 5000

5000 students appeared in the examination.

4 0
3 years ago
10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!
In-s [12.5K]
Remark
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.

y = \int (cos(x) + sin(x) ) \, dx = \int{cos(x) \,dx + \int sin(x) \,dx
y = sin(x)  -  cos(x) + C 
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0  -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1

y = sin(x) - cos(x) - 1  <<<<< Answer

Problem Two
Remember that y =  \int\ { \frac{1}{x} } \, dx = ln(|x|) + C
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C  = 0
3 + C = 0
C = - 3

y = ln(|x|) - 3  <<<< Answer
7 0
3 years ago
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