In the case above, the correct vectors are:
- <25.98, -15>.
- <1.71, 4.7>.
<h3>What is the ship vector about?</h3>
The solution for the Ship's vector are:
Note that the Horizontal aspect = 30 cos 30
= 25.98.
For the Vertical aspect = 30 sin(-30)
= -15.
Hence it will be <25.98, -15>.
In regards to the current's vector:
The Horizontal aspect= 5 sin 20
= 1.71.
The Vertical aspect = 5 cos 20
= 4.7.
Hence it will be <1.71, 4.7>.
Therefore, In the case above, the correct vectors are:
- <25.98, -15>.
- <1.71, 4.7>.
Learn more about vectors from
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Answer:
Step-by-step explanation:
Picture 1
In right triangle ABC,
Side AB is the opposite side of angle C.
Picture 2
In triangle MKL,
tan(∠M) = 
= 
= 
Option (1) is the answer.
Picture 3
In ΔXYZ,
sin(∠Z) = 
= 
For the length of XY we will apply Pythagoras theorem in ΔXYZ,
XZ² = XY² + YZ²
XY² = XZ² - YZ²
= (40)² - (32)²
XY = √576
= 24
sin(Z) = 
sin(Z) = 
Picture 4
In right triangle DEF,
Cos(D) = 
= 
= 
= 
Picture 5
In ΔABC,
tan(63°) =
tan(63°) = 
AB = 
AB = 
AB = 4.0762 ≈ 4 m
Option (3) will be the answer.
Answer:
363
Step-by-step explanation:
11x11=121
((11x11)÷2)x4=11x11x2=121x2=242
121+242=363
First, lets transform the given vector into an unit vector (dividing by its module)
UnitVec = 4/5 i + 3/5 j
Then lets change this vector into a polar form
UnitVec = 1. with angle of 36.869 degrees taking as a reference the i vector
Then, the probem tells us that the vectors u and v make an angle of 45 degrees with UnitVec, so lets add+-45 to the vector in polar form
U = 1*[cos(36.869 +45)i + sin(36.869 +45)j] = 0.1414 i + 0.9899 j
V = 1*[cos(36.869 -45)i + sin(36.869 -45)j] = 0.9899 i - 0.1414 j
Answer:
y = 1.5x
Step-by-step explanation:
