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Dmitriy789 [7]
3 years ago
6

A chemical manufacturer wants to lease a fleet of 28 railroad tank cars with a combined carrying capacity of 564,000 gallons. Ta

nk cars with three different carrying capacities are​ available: 6,000 ​gallons,12,000 gallons, and 24,000 gallons. How many of each type of tank car should be​ leased?
Let x1 be the number of cars with a 6,000 gallon​ capacity, x2 be the number of cars with a 12,000 gallon​ capacity, and x3 be the number of cars with a 24,000 gallon capacity. Select the correct choice below and fill in the answer boxes within your choice.
Mathematics
1 answer:
yan [13]3 years ago
3 0

You forgot to give the choices so I will solve the problem in detail step-by-step explanation and then you can select the correct choice and fill in the answer boxes within your choice correctly.

Given the criteria stated in the problem, we can obtain the  following linear system:

\left \{ {{x_{1} + x_{2} + x_{3}  = 28} \atop {6000x_{1} + 12000x_{2}  + 24000x_{3} =564000}} \right.

The corresponding augmented matrix is

\left[\begin{array}{ccc|c}1&1&1&28\\6000&12000&24000&564000\end{array}\right]

\left[\begin{array}{ccc|c}1&1&1&28\\6000&12000&24000&564000\end{array}\right]  \frac{1}{6000} R_{1}→ R_{2}\left[\begin{array}{ccc|c}1&1&1&28\\1&2&4&94\end{array}\right] R_{2} +(-1)R_{1}

→R_{2} \left[\begin{array}{ccc|c}1&1&1&28\\0&1&3&66\end{array}\right]  R_{1} +(-1)R_{2}→R_{1} \left[\begin{array}{ccc|c}1&0&-2&-38\\0&1&3&66\end{array}\right]

The linear system corresponding to the reduced form is

\left \{ {{x_{1} -2x_{3} =-38} \atop {x_{2}+3x_{3}  =66}} \right.

Since x_{3} is the free variable, we let x_{3} =t, where t is any real number. Then the general solution can be written as follows:

\left \{ \begin{array}{ccc}x_{1} =&-38&+2t\\x_{2} =&66&-3t\\x_{3} =&t\end{array}\right

where t is any real number.

However, the definitions of x_{1},x_{2} and x_{3} imply that the solutions must be non-negative integers.  Therefore, we need to derive the possible range of values of t such that the general solution make sense for this problem:

\left \{ \begin{array}{ccc}-38&+2t&\geq 0\\66&-3t&\geq 0\\t&&\geq 0\end{array}\right

Solving the inequalities, we finally obtain all the relevant solutions  to the linear system:

\left \{ \begin{array}{ccc}x_{1} =&-38&+2t\\x_{2} =&66&-3t\\x_{3} =&t\end{array}\right

where t is any integer such that 19 \leq t \leq 22.

Thus, you just need to apply the above solution to the choices given to you and fill in the answer boxes correctly.

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2. Sometimes

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Step-by-step explanation:

1. Quadratic function : in which maximum power of x is two.

The roots of quadratic function can be either equal or different.

For example:

  • x^{2} -2x+1 will have two equal roots i.e. 1 and 1.
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2. Cubic function has atleast 1 real root.

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If the coefficients are imaginary in nature, then this is not true.

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Cubic equation x^3 +i = 0 does not have any real root.

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3. A function with degree 5 i.e. maximum power of x as 5 will have 5 roots.

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Two complex solutions are also possible for a quadratic function.

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