You forgot to give the choices so I will solve the problem in detail step-by-step explanation and then you can select the correct choice and fill in the answer boxes within your choice correctly.
Given the criteria stated in the problem, we can obtain the following linear system:

The corresponding augmented matrix is
![\left[\begin{array}{ccc|c}1&1&1&28\\6000&12000&24000&564000\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2628%5C%5C6000%2612000%2624000%26564000%5Cend%7Barray%7D%5Cright%5D)
→ ![R_{2}\left[\begin{array}{ccc|c}1&1&1&28\\1&2&4&94\end{array}\right] R_{2} +(-1)R_{1}](https://tex.z-dn.net/?f=R_%7B2%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2628%5C%5C1%262%264%2694%5Cend%7Barray%7D%5Cright%5D%20R_%7B2%7D%20%2B%28-1%29R_%7B1%7D)
→
→![R_{1} \left[\begin{array}{ccc|c}1&0&-2&-38\\0&1&3&66\end{array}\right]](https://tex.z-dn.net/?f=R_%7B1%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%26-2%26-38%5C%5C0%261%263%2666%5Cend%7Barray%7D%5Cright%5D)
The linear system corresponding to the reduced form is

Since
is the free variable, we let
, where
is any real number. Then the general solution can be written as follows:

where
is any real number.
However, the definitions of
,
and
imply that the solutions must be non-negative integers. Therefore, we need to derive the possible range of values of
such that the general solution make sense for this problem:

Solving the inequalities, we finally obtain all the relevant solutions to the linear system:

where
is any integer such that 19
22.
Thus, you just need to apply the above solution to the choices given to you and fill in the answer boxes correctly.