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barxatty [35]
3 years ago
7

Tell whether the equation has one, zero, or infinitely many solutions:9(x - 4) +15=9x – 21​

Mathematics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

Infinite solutions

Step-by-step explanation:

Simplify both sides, subtract 9x, and add 21x to both sides and you will get 0 = 0 so there is infinite solutions.

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A typical small bag of colored candies has about 135 candies in it, 27 of which is blue. At the rate, how many blue candies woul
Zielflug [23.3K]

Answer:

in a pile of 1000 colored candies, you'll find 200 of which are blue

Step-by-step explanation:

135 ÷ 27 = 5

ratio: 5:1

1000÷5 = 200

feel free to correct me if I'm wrong

7 0
3 years ago
Read 2 more answers
Simplify the expression: 2(x+h)^2 - 2x^2 over (x+h) - x
Karolina [17]

Answer:

4x

Step-by-step explanation:


4 0
3 years ago
4z-(-3z) can you help me​
Korvikt [17]

Answer:

7z

Step-by-step explanation:

4z-(-3z).

Two negatives equal a positive only <u>when they are right next to each other.</u>

4z+3z=7z. Hope this helps :D

8 0
2 years ago
Find the value of x ​
maks197457 [2]

Answer:

Step-by-step explanation:

∠S=180-(54+62)=180-116=64°

using sin formula

\frac{x}{sin~64} =\frac{7}{sin~62} \\x=\frac{7~sin~64}{sin~62} \approx 7.1256 \approx 7.13

6 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
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