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Mashcka [7]
3 years ago
12

Evaluate: 2(6+4) – 3(5)

Mathematics
2 answers:
Ber [7]3 years ago
7 0

Answer:

5

Step-by-step explanation:

Simplify the expression.

2(6+4) - 3(5)

2(10) - 3(5)

20 - 15 = 5

zmey [24]3 years ago
6 0

Answer:5

Step-by-step explanation:

Add 6 and 4

2*10-3*5

Multiply 2 by 10

20-3*5

Multiply -3 by 5

20-15

Subtract 15 from 20

5

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4. An ice cream shop wants to design a super straw to serve with its extra thick milkshakes that is double both the width and th
Andre45 [30]

Answer:

A. \\ 0.50cm^{2}; B. \\ 5.03cm^{3}; C. 19min

Step-by-step explanation:

<h3>First Step: Determine the size of the new straw</h3>

The size of the new straw is "double both the width and thickness of a standard straw". "A standard straw is 4mm in diameter and 0.5mm thick". So, the new straw is, then:

\\ 2 * 4mm = 8mm or, equivalently, \\ \frac{1cm}{10mm} * 8mm = 0.8cm (<em>Diameter</em>).

\\ 2 * 0.5mm = 1mm or, equivalently, \\ \frac{1cm}{10mm} * 1mm = 0.1cm (<em>Thickness</em>).

<h3>Second Step: Determine the cross-sectional area of the new straw</h3>

The cross-section area is "a section made by a plane cutting anything transversely, especially at right angles to the longest axis" <em>Cross-section</em> (2020), In Dictionary.com. Therefore, the area here is that of a circle:

\\ A_{cross_{section}}= \pi * r^2,

Where \\ \pi = 3.1415926535897932384626...., and represents the ratio between a circle's circumference and its diameter, and <em>r</em> is the circle's radius or its diameter divided by 2.

Then, the area is:

\\ A_{cross_{section}} = \pi * (\frac{0.8cm}{2})^2 = \pi * (0.4cm)^2= 0.502655cm^2, rounded to <em>the nearest hundredth</em>:

\\ A_{cross_{section}} = 0.50cm^2

<h3>Third Step: Determine the maximum volume of milkshake that can be in the straw at one time</h3>

The new straw is 10cm long and its cross-section is, approximately,

\\ A_{cross_{section}} = 0.502655cm^2

Since the straw is a cylinder, and the volume of a cylinder is:

\\ V_{straw} = \pi * r^2 * h = A_{cross_{section}} * h, where <em>h</em> is the height of the straw. In this case is 10cm long.

So, <em>the maximum volume of milkshake that can be in the straw at one time</em> is the volume of the straw:

\\ V_{straw} = A_{cross_{section}}*h = 0.502655cm^2 * 10cm = 5.02655cm^3, rounded to the <em>nearest hundredth</em>:

\\ V_{straw} = 5.03cm^3

<h3>Fouth Step: Determine the minimum amount of time that it will take Corbin to drink the milkshake</h3>

A large milkshake is 950mL, and we know that:

\\ 1000mL = 1000cm^3 = 1L

So,

\\ 1mL = 1cm^3, therefore, \\ 950mL = 950cm^3

"Corbin withdraws the full capacity of a straw 10 times a minute" or Corbin withdraws:

\\ 10*V_{straw} = 10*5.02655cm^3 = 50.2655cm^3 every minute.

The large milkshake is \\ 950cm^3 . If Corbin withdraws \\ \frac{50.2655cm^3}{min}, <em>the minimum amount of time that it will take him to drink the milkshake</em> is:

\\ \frac{950cm^3}{\frac{50.2655cm^3}{min}} = \frac{950}{50.2655}*\frac{cm^3}{cm^3}*min = 18.8996min, since \\ \frac{cm^3}{cm^3} = 1.

Rounded to the nearest minute, the minimum amount of time is 19min.

8 0
3 years ago
11. The cost of a new sled is $144.95. If Walmart marks this price up by
uysha [10]

Answer:

$237.72

Step-by-step explanation:

8 0
2 years ago
Use your answer in part (a) to find the two values of m for which (m-2)2 -4(m-2)+2=0​
Olegator [25]

Answer:

Step-by-step explanation:

Replace m - 2 with x.  Then we have x^2 - 4x + 2 = 0.

Completing the square, we get x^2 - 4x + 4 - 4 + 2 = 0, or

x^2 - 4x + 4 - 2 = 0, or

(x - 2)^2 - 2 = 0, or (x - 2)^2 = 2

Solve for x:  Take the square root of both sides.  Then:

x - 2 = ±√2 and x = 2 + √2 and x = 2 - √2

But x = m - 2; therefore, x = m - 2 = 2 - √2.  Solving for m, we get

m = 4 - √2.    

Also:  m - 2 = 2 + √2 leads to m = 4 + √2.  

The given equation is true for these two values of m.        

5 0
3 years ago
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