<span>c)1 + 2cot^2x + 2cscx cotx
because cosc^2x=1+cot^2x</span>
Answer:
m∠ MNL = 78º
Step-by-step explanation:
<u>Arcs meassures </u>
mML = (11x - 5)º
mJK = (4x + 26)°
<u>Angle meassure</u>
m∠MNL = (10 x – 12)º
______________________
angle measure = average of arcs
m∠MNL = (mML+ mJK)/2
Replacing
(10x – 12)º = ((11x - 5)º + (4x + 26)° )/ 2
10x -12 = (15x + 21 )/2
10x - 7.5x = 10.5 + 12
2.5x = 22.5
x= 9
m∠MNL = (10 x – 12)º
= 90 - 12
= 78º
20m measurement that’s what is equal to 10
A. is the answer fellow user
Given :
<span>Triangle fgh is inscribed in circle o
</span>
oh = 6 = radius of the circle
<span>∵ fh is congruent to og
</span>
<span>∴ fh = og = radius og the circle = 6
</span>
<span>∵ of = radius of the circle = 6
</span>
<span>∴ oh = fh = of = radius of the circle = 6
</span>
∴ Δ foh is Equilateral Triangle
<span> </span>∴∠ foh = 60° ⇒⇒⇒ property of <span>the equilateral Triangle
</span>
∵ total area of the circle = π r² and total central angle of the circle = 360°
∴ Area of sector foh = (60°/360°) * π r²
∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85
The answer is:
<span>the area of the sector formed by angle foh
= 18.85</span>