??? What do you need help with/
Answer:
I think no because the critical properties distinguishing life is adaptation to changing environment and self replication of the information encoding the life process. Fire does not change its process to adapt to its environment, e.g. moving toward more fuel or storing and conserving fuel when it is in short supply.
Hope this help you!:)
Explanation:
The angular momentum is given by the moment of inertia, multiplied by the angular speed of the rotating body:
![L=I\omega](https://tex.z-dn.net/?f=L%3DI%5Comega)
The angular speed is given by:
![\omega=2\pi f\\\omega=2\pi 5.2\frac{rev}{s}\\\omega=32.67\frac{rad}{s}](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%20f%5C%5C%5Comega%3D2%5Cpi%205.2%5Cfrac%7Brev%7D%7Bs%7D%5C%5C%5Comega%3D32.67%5Cfrac%7Brad%7D%7Bs%7D)
Now, we calculate the angular momentum:
![L=0.32kg\cdot m^2(32.67\frac{rad}{s})\\L=10.45\frac{kg\cdot m^2}{s}](https://tex.z-dn.net/?f=L%3D0.32kg%5Ccdot%20m%5E2%2832.67%5Cfrac%7Brad%7D%7Bs%7D%29%5C%5CL%3D10.45%5Cfrac%7Bkg%5Ccdot%20m%5E2%7D%7Bs%7D)
The average torque is defined as:
![\tau=I\alpha](https://tex.z-dn.net/?f=%5Ctau%3DI%5Calpha)
is the angular acceleration, which is defined as:
![\alpha=\frac{\omega_f-\omega_0}{t}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7B%5Comega_f-%5Comega_0%7D%7Bt%7D)
We have to calculate
:
![\omega_f=2\pi (2.75\frac{rad}{s})\\\omega_f=17.28\frac{rad}{s}](https://tex.z-dn.net/?f=%5Comega_f%3D2%5Cpi%20%282.75%5Cfrac%7Brad%7D%7Bs%7D%29%5C%5C%5Comega_f%3D17.28%5Cfrac%7Brad%7D%7Bs%7D)
Now, we calculate the angular acceleration:
![\alpha=\frac{17.28\frac{rad}{s}-32.67\frac{rad}{s}}{12s}\\\alpha=-1.28\frac{rad}{s^2}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7B17.28%5Cfrac%7Brad%7D%7Bs%7D-32.67%5Cfrac%7Brad%7D%7Bs%7D%7D%7B12s%7D%5C%5C%5Calpha%3D-1.28%5Cfrac%7Brad%7D%7Bs%5E2%7D)
Finally, we can know the average torque:
![\tau=0.32kg\cdot m^2(-1.28\frac{rad}{s^2})\\\tau=-0.41N\cdot m](https://tex.z-dn.net/?f=%5Ctau%3D0.32kg%5Ccdot%20m%5E2%28-1.28%5Cfrac%7Brad%7D%7Bs%5E2%7D%29%5C%5C%5Ctau%3D-0.41N%5Ccdot%20m)
Let's call
![f_n](https://tex.z-dn.net/?f=f_n)
the frequency of the nth-harmonic and
![f_{n+1}](https://tex.z-dn.net/?f=f_%7Bn%2B1%7D)
the frequency of the (n+1)th harmonic, wish is the next harmonic.
Since the frequency of the nth-harmonic is n times the fundamental frequency f1:
![f_n = n f_1](https://tex.z-dn.net/?f=f_n%20%3D%20n%20f_1)
then the difference between two successive harmonics is equal to the fundamental frequency of the tube:
![f_{n+1}-f_n = (n+1)f_1 - nf_1 = nf_1 + f_1 - nf _1 = f_1](https://tex.z-dn.net/?f=f_%7Bn%2B1%7D-f_n%20%3D%20%28n%2B1%29f_1%20-%20nf_1%20%3D%20nf_1%20%2B%20f_1%20-%20nf%20_1%20%3D%20f_1)
so, by using 350 Hz and 280 Hz as successive harmonics, we find the fundamental frequency of the tube:
![f_1 = 350 Hz - 280 Hz = 70 Hz](https://tex.z-dn.net/?f=f_1%20%3D%20350%20Hz%20-%20280%20Hz%20%3D%2070%20Hz)
The wavelength of the first harmonic is twice the length of the tube:
![\lambda = 2 L=2 \cdot 1.70 m=3.40 m](https://tex.z-dn.net/?f=%5Clambda%20%3D%202%20L%3D2%20%5Ccdot%201.70%20m%3D3.40%20m)
And since we know both frequency and wavelength, we can find the speed of the wave in the tube, which is the speed of sound in the gas in the tube:
Explanation:
That means no Gravitational Force (g) acting on the object.
If we look the Newton's 2nd Law , we will see that the force (F) and gravitational force (g) is dependent each other , and the mass (m) is a coefficient between them.