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3 years ago

An empty can is floating in a large beaker of water. The volume of water displaced in the beaker is equal to _____.

Physics

1 answer:

Mandarinka [93]3 years ago

4 0

The volume of water displaced in the beaker is equal to the volume of the submerged part of the can.

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Do energy drinks actually provide energy?

denis-greek [22]

Answer:

Most energy drinks contain large amounts of caffeine, which can provide a temporary energy boost. Some energy drinks contain sugar and other substances. The boost is short-lived, however, and may be accompanied by other problems.

Explanation:

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2 years ago

Read 2 more answers

Where do we hear loud sound, at antinode or node?

tester [92]

Answer:

node

Explanation:

on the graph node is higher than antinode

so it can get or hear loud sounds faster

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2 years ago

A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound

Strike441 [17]

Answer:

$5.997m/s$

Explanation:

We were told to calculate the speed of the ball,

Given speed of sound as 340 m

And we know that the sound of the ball hitting the pins is at 2.80 s after the ball is released from his hands.

Speed of ball = distance traveled/(time of hearing - time the sound travels).

Speed= S/t

Where S= distance traveled

t= time of hearing - time the sound travels

time=time for ball to roll+timefor sound to come back.

time of sound=16.5/340

=0.048529secs

solving for speedof ball

Then,Speed of ball = distance traveled/(time of hearing - time the sound travels).

=16.5/(2.80-0.048529) m/s = 5.997m/s

Therefore, the speed of the ball is

5.997m/s

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2 years ago

The space probe Deep Space 1 was launched on October 24th, 1998 and it used a type of engine called an ion propulsion drive. An

Xelga [282]

Answer:

Explanation:

mass of probe m = 474 Kg

initial speed u = 275 m /s

force acting on it F = 5.6 x 10⁻² N

displacement s = 2.42 x 10⁹ m

A )

initial kinetic energy = 1/2 m u² , m is mass of probe.

= .5 x 474 x 275²

= 17923125 J

B )

work done by engine

= force x displacement

= 5.6 x 10⁻² x 2.42 x 10⁹

= 13.55 x 10⁷ J

C ) Final kinetic energy

= Initial K E + work done by force on it

= 17923125 +13.55 x 10⁷

= 1.79 x 10⁷ + 13.55 x 10⁷

= 15.34 x 10⁷ J

D ) If v be its velocity

1/2 m v² = 15.34 x 10⁷

1/2 x 474 x v² = 15.34 x 10⁷

v² = 64.72 x 10⁴

v = 8.04 x 10² m /s

= 804 m /s

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2 years ago

How do I calculate the efficiency of motor

zepelin [54]

Answer:

the formula is efficiency = output / input × 100%

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2 years ago