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3 years ago

If 36C ofcharge pass through a write in 4s current is it carrying?

Physics

1 answer:

charle [14.2K]3 years ago

8 0

Answer:

The current flowing through the wire is 9 A.

Explanation:

Given;

quantity of charge passing through the wire, Q = 36 C

duration of the charge flow, t = 4 s

The current flowing through the wire is calculated as;

Q = It

I = Q / t

where;

I is the current flowing in the wire

I = 36/4

I = 9 A

Therefore, the current flowing through the wire is 9 A.

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A 2.7-cm-tall object is 20 cm to the left of a lens with a focal length of 10 cm . A second lens with a focal length of 48 cm is

irina1246 [14]

Answer

given,

height of object = 2.7 cm

distance left of lens (u₁)= 20 cm

focal length of lens(f₁)= 10 cm

the distance of image

$\dfrac{1}{f_1}=\dfrac{1}{u_1}+\dfrac{1}{v_1}$

$\dfrac{1}{v_1}=\dfrac{1}{f_1}-\dfrac{1}{u_1}$

$\dfrac{1}{v_1}=\dfrac{1}{10}-\dfrac{1}{20}$

v₁ = 20 cm

magnification of first lens

$m_1= -\dfrac{v}{u}$

$m_1=-\dfrac{20}{20}$

m₁ = -1

distance of object from the second lens

u₂ = 52-20 = 32 cm

f₂ = 48 cm

now,

$\dfrac{1}{f_2}=\dfrac{1}{u_2}+\dfrac{1}{v_2}$

$\dfrac{1}{v_2}=\dfrac{1}{f_2}-\dfrac{1}{u_2}$

$\dfrac{1}{v_2}=\dfrac{1}{48}-\dfrac{1}{52}$

v₁ = 624 cm

magnification of first lens

$m_1= -\dfrac{v}{u}$

$m_1=-\dfrac{624}{52}$

m₁ = -12

total magnification

m = m₁ m₂

m = (-1)(-12)

m = 12

height of image

$m =-\dfrac{h'}{h}$

$12=-\dfrac{h'}{2.7}$

h' = -32.4 cm

a) distance between image and second lens is equal to 624 cm

b) height of image is equal to 32.4 cm

4 0

3 years ago

A Rankine oval is formed by combining a source-sink pair, each having a strength of 36 ft2/s and separated by a distance of 15 f

Rashid [163]

Answer:

0.28 ft

Explanation:

We are given that

Strength=m= $36ft^2/s$

Distance between source and sink=15 ft

Distance between the sink of the source and origin= $a=\frac{15}{2}$ ft

Uniform velocity, U=12 ft/s

We have to find the length of the oval.

Formula to find the half length of the body

$\frac{l}{a}=(\frac{m}{\pi Ua}+1)^{\frac{1}{2}}$

Where a=Distance between sink of source and origin

U=Uniform velocity

m=Strength

l=Half length

Using the formula

$\frac{l}{\frac{15}{2}}=(\frac{36}{\pi\times 12\times \frac{15}{2}}+1)^{\frac{1}{2}}$

$l=\frac{2}{15}(\frac{36}{\pi\times 12\times \frac{15}{2}}+1)^{\frac{1}{2}}$

$l=0.14$

Length of oval= $2l=2(0.14)=0.28 ft$

8 0

3 years ago

A ball moving 2 ft/s rolls off a table (on earth) that is 32 inches high. How long will it take the ball to hit the floor answer

mart [117]

Answer:When the ball rolls off the edge of the table, it will continue moving forward at 2.0 m/s until it hits the floor.

Explanation:This is what I would say is the answer bc I had to do reasearch on a lot of this for my work this year so if its not im veery sorry

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3 years ago

What is a real-world application that depends on the relationship between distance, average speed, and time?

sertanlavr [38]

time thats the anwser

6 0

4 years ago

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If you changed the surface of the incline the car is rolling down, how might that impact the distance and speed the car travels?

Keith_Richards [23]

Explanation: As the angle is increased the acceleration of the object is increased as the angle increases the component of the force parallel to the incline increases and the component of forced perpendicular to the inclined decreases it is the parallel component of the weight vector that causes the acceleration.

6 0

3 years ago

If 36C ofcharge pass through a write in 4s current is it carrying?​

If 36C ofcharge pass through a write in 4s current is it carrying?