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leva [86]
3 years ago
8

What unit of time on Earth is based on the revolution of the Earth around the Sun?

Physics
2 answers:
Dafna11 [192]3 years ago
7 0

Answer:

I believe it's C. Year.

Explanation:

Hope this helps! ^^

ollegr [7]3 years ago
3 0

C.) Year

i hope this helped! please mark me as brainliest and 5 stars >:)

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1. Which of the following is not included
Harrizon [31]

Answer:

cartilage

Explanation:

8 0
3 years ago
A ball is dropped from a building taking 3sec to fall to the ground. Calculate:
GenaCL600 [577]

Answer:

Vf = 29.4 m/s

h = 44.1 m

Explanation:

Data:

  • Initial Velocity (Vo) = 0 m/s
  • Gravity (g) = 9.8 m/s²
  • Time (t) = 3 s
  • Final Velocity (Vf) = ?
  • Height (h) = ?

==================================================================

Final Velocity

Use formula:

  • Vf = g * t

Replace:

  • Vf = 9.8 m/s² * 3s

Multiply:

  • Vf = 29.4 m/s

==================================================================

Height

Use formula:

  • \boxed{h=\frac{g*(t)^{2}}{2}}

Replace:

  • \boxed{h=\frac{9.8\frac{m}{s^{2}}*(3s)^{2}}{2}}

Multiply time squared:

  • \boxed{h=\frac{9.8\frac{m}{s^{2}}*9s^{2}}{2}}

Simplify the s², and multiply in the numerator:

  • \boxed{h=\frac{88.2m}{2}}

It divides:

  • \boxed{h=44.1\ m}

What is the velocity when falling to the ground?

The final velocity is <u>29.4 meters per seconds.</u>

How high is the building?

The height of the building is <u>44.1 meters.</u>

3 0
3 years ago
a car traveling at 30m/s notices an accident about 65m up the road. The car's brakes are capable of decelerating at a rate of 6.
uysha [10]
Yes because you would have at least 3 car spaces
4 0
3 years ago
jill's car has a maximum acceleration of 8.7 miles per hour per second. how many seconds does it take her to acceleration from 0
amm1812
T = ?
v1 = 0mph
v2 = 60mph
a = 8.7mph/s

a =  \frac{v2 - v1}{t}&#10; \\ t =  \frac{v2-v1}{a}&#10; \\ t =  \frac{60mph - 0mph}{8.7mph/s}&#10; \\ t = 6.90s

Therefore, it takes 6.90 seconds for Jill to accelerate from 0 to 60 miles per hour.
4 0
4 years ago
A 20.00 kg lead sphere is hanging from a hook by a thin, massless wire 2.80 m long and is free to swing in a complete circle. Tr
Tema [17]

The minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 58.5 m/s.

<h3>Minimum speed for the object not fall out of the circle</h3>

The minimum speed if given by tension in the wire;

T + mg = ma

T + mg = m(v²)/R

tension must be zero for the object not fall

0 + mg = mv²/R

v = √(Rg)

<h3>Final speed of the two mass after collision</h3>

Use the principle of conservation of energy

K.Ef  = K.Ei + P.E

¹/₂mvf² = ¹/₂mv² + mg(2R)

¹/₂vf² = ¹/₂v² + g(2R)

¹/₂vf² = ¹/₂(Rg) + g(2R)

vf² = Rg + 4Rg

vf² = 5Rg

vf = √(5Rg)

vf = √(5 x 2.8 x 9.8)

vf = 11.7 m/s

<h3>Initial speed of the dart</h3>

Apply principle of conservation of linear momentum for inelastic collision;

5v = vf(20 + 5)

5v = 11.7(25)

5v = 292.5

v = 58.5 m/s

Learn  more about linear momentum here: brainly.com/question/7538238

#SPJ1

3 0
2 years ago
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