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V125BC [204]
3 years ago
5

IS IT C OR D?! HELP ME PLS

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

D

Step-by-step explanation:

To find this, we need to find the points that are the steepest (or have larger slope). We have the points (2, 3), (4, 11), and (6, 23). The line that has (2, 3) and (4, 11) has a slope of 4, and the line with (4, 11) and (6, 23) has a slope of 6. Therefore the answer is D.

Note: Simple eyeballing will do the trick too!

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Help fast !!!! I need to get this done before I go to school ixl AA.1
Lorico [155]

Answer:

slope = - \frac{7}{5}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 5, 0) and (x₂, y₂ ) = (0, - 7 ) ← 2 points on the line

m = \frac{-7-0}{0-(-5)} = \frac{-7}{0+5} = \frac{-7}{5} = - \frac{7}{5}

4 0
3 years ago
a student reads at a rate of 16 pages per day which ordered pair would be on a graph of its relationship
mojhsa [17]
I found the choices that should have been included in this problem.
a) (1.5,26)
b) (2.25,30)
c) (5.5,88)
d) (7.25,110)

y = 16x
choice a. y = 16(1.5) = 24
choice b. y = 16(2.25) = 36
choice c. y = 16(5.5) = 88
choice d. y = 16(7.25) = 116

The correct answer is choice c. (5.5, 88)
8 0
3 years ago
If A || B and B | y, then ?
aniked [119]

Answere: I believe that the answere is C.

Step-by-step explanation:

Well,since the lines A and B are paralel and the line y is not paralel with any of then y and A are not paralel.Plus there is not a line called x in this particular equazion.If you have any questions , please contact me.

Yours sincerely,

Manos

8 0
3 years ago
Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3
nlexa [21]

Answer:

(x,y) = (5,-6)

Step-by-step explanation:

\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\

                     ~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)

\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\

\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5

y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6

\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)

7 0
2 years ago
.................................................
Andrej [43]

Answer: …………..

Step-by-step explanation:

……………..

4 0
3 years ago
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