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shusha [124]
3 years ago
7

Rewrite the expression with the given base.

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0

The expression given to us is: 64^2x and we have to rewrite it with a base of 8 .

We know that 64 can be written in terms of 8 as the squared of 8 as:64=8^2.

Thus, the expression, 64^{2x} can be rewritten as:

64^{2x}=(8^2)^{2x}

Now, using the rules of exponents we get:

(8^2)^{2x}=8^{2\times 2x}=8^{4x}

\therefore 64^{2x}=8^{4x}

Thus, out of the given options, <u>option C is the correct option</u>.


satela [25.4K]3 years ago
3 0
C. 8^4x
64^2x = 4096x
8^4x= 4096x
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Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.
Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0
3 years ago
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alekssr [168]
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3 years ago
Kent and Bradley both work at a car dealership. Kent makes $10/hour + 3% on the amount of sales he completes. Bradley only makes
Masteriza [31]

Answer: There is difference of $660 in their paychecks.

Step-by-step explanation:

Since we have given that

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So, the equation for Kent becomes,

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So, the equation for Bradley becomes,

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hence, the difference between of their paychecks is given by

\$3400-\$2740\\\\=\$660

Therefore, there is difference of $660 in their paychecks.

3 0
2 years ago
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