To answer this question, you will represent the amount of yards rushed by each running back.
x - Running back #1
9x - Running back #2
The combined yards was 1550, so put these together in an addition equation with a total of 1550. Solve for x.
x + 9x = 1550
10x = 1550
x = 155
Running back #1 rushed 155 yards, and running back #2 rushed for 1395 yards.
Answer:
213
Step-by-step explanation:
1. Set up an equation (as you have done there)
2. divide the first digit, so in this case you want to divide 34 / 7 which doesn't work so your gonna add another number 72 and how many times can 34 go into 72 that will be twice so 34 x 2 is 68, and you put the 2 at the top where the line is over 2
3. and then you subtract 72 and 68 and then you get 4.
4. after that you start the process again but doing it by just adding another number so in this case you would 724 at the next step. you stop when you have run out of numbers to add
hope i helped
Alright here we go...
<u>(-18) + (-15) - 23</u>
-33 - 23
= -56
<u>15-18+23</u>
-3 + 23
= 20
so I don't know how you want me to compare it but,
(-18) + (-15) - 23 < 15-18+23
Answer:
the first and second option
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Given
f(x) = (x - 4)(2x - 1)²(x - 2)²
To find the roots equate f(x) to zero, that is
(x - 4)(2x- 1)²(x - 2)² = 0
Equate each of the factors to zero and solve for x
x - 4 = 0 ⇒ x = 4
2x - 1 = 0 ⇒ x = 
← with multiplicity 2
x - 2 = 0 ⇒ x = 2 ← with multiplicity 2
Hence the roots are
{ 4, , 2 }
Given
f(x) = x³ + 4x² + 7x + 6
Note that
f(- 2) = (- 2)³ + 4(- 2)² + 7(- 2) + 6 = - 8 + 16 - 14 + 6 = 0
Since f(- 2) = 0 then by the factor theorem x = - 2 is a root and (x + 2) a factor
Using synthetic division
- 2 | 1 4 7 6
- 2 - 4 - 6
--------------
1 2 3 0
Thus
f(x) = (x + 2)(x² + 2x + 3)
Solve x² + 2x + 3 using the quadratic formula
with a = 1, b = 2 and c = 3
x = (- 2 ± 
) / 2
= ( - 2 ± 
) / 2
= ( - 2 ± 
) / 2
= (- 2 ± 2i
) / 2
= - 1 ± i
Hence roots are
{ - 2, - 1 + i, - 1 - i }
