Which statement is true about the relation shown on the graph below?

PLEASE HELP ME WITH THIS!!! Also make sure I can understand it it is also preferable to post a picture but either one will do th

rusak2 [61]

You can use a Scatter Plot to show the relationship between two sets of data. As you can see, this Scatter Plot shows the Speed in meters per second (m/s) versus the Distance in meters (m).

In the figure attached, the first point is (2,5), you need to move 2 on the axis "speed (m/s)" and 5 on the axis "distance (m)". This means that the first point is the intersection between 2 m/s and 5 m. The second point is (3,8), then, you need to move 3 on the axis "speed (m/s)" an 8 on the axis "distance (m)" You must do this with the other values.

5 0

3 years ago

Identify the interval on which the quadratic function is positive.

Alenkasestr [34]

Answer:

$\textsf{1. \quad Solution: $1 < x < 4$,\quad Interval notation: $(1, 4)$}$

$\textsf{2. \quad Solution: $-2 < x < 4$,\quad Interval notation: $(-2, 4)$}$

Step-by-step explanation:

<h3>Question 1</h3>

The intervals on which a quadratic function is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a negative leading coefficient, the parabola opens downwards. Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x-1=0 \implies x=1$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is positive is:

Solution: 1 < x < 4
Interval notation: (1, 4)

<h3>Question 2</h3>

The intervals on which a quadratic function is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a positive leading coefficient, the parabola opens upwards. Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x+2=0 \implies x=-2$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is negative is:

Solution: -2 < x < 4
Interval notation: (-2, 4)

3 0

1 year ago

8 is greater than or equal to x, and 4 is less than x

eimsori [14]

Answer:

8>x (greater sign needs a line under it)

4<x

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

20% off coupon is always a better deal than $5.00 off. true or false

Phantasy [73]

False, it depends on how much the item you are buying costs

6 0

4 years ago

Read 2 more answers

6feet man casts a 2.7 feet shadow at the same time a tree casts a 11.4 feet shadow. how tall is the tree?

Zepler [3.9K]

You can set this up as a proportion.

6/2.7=x/11.4

Cross multiply.

2.7x=68.4

Divide by 2.7 to solve for x

25.3333=x

The tree is 25 and 1/3 feet tall

7 0

3 years ago