Use the quadratic formula to find the solution to the quadratic equation in the box below.

Mathematics

1 answer:

nekit [7.7K]3 years ago

4 0

The solution to the quadratic equation is option D

You might be interested in

Which expression is equivalent to 5.4+3.4w-1.8w +5.8 A) 7(1.6+w) B) 1.6(7+w) C) 1.6(7w) D) 1.6(0.25+w)

Bad White [126]

Do 5.4 plus 5.8 then do 3.4w minus 1.8w and whatever you get for each is your key to the expression. So if you were to solve the answers like A you would do 7(1.6+w) and see what you would get. Obviously A isn't the answer. Sorry, this is hard to explain. But the answer is C

6 0

4 years ago

Rotate the vector (0,2) 270 degrees counterclockwise about the origin

SashulF [63]

<h3>Answer: (2,0)</h3>

Explanation:

The vector (0,2) points directly north and the length of this vector is 2 units. It's the distance from (0,0) to (0,2).

When rotating 270 degrees counterclockwise, we'll turn to the left or westward direction (90 degrees so far) then at some point aim directly south (180 degrees so far) and finally ultimately end up pointing directly east (after getting to 270). So that's how we go from (0,2) to (2,0).

If you were to go clockwise, then everything flips and you'll ultimately end up pointing directly west. The length of the vector stays the same the whole time.

3 0

3 years ago

Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .

Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1$

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

$y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11$