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icang [17]
3 years ago
6

Can somebody -3(x+4)+6

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0
-3(x+4)+6
-3x-12+6
-3x-6 <= that’s the answer but just in case you want to find what “x” is:
-3x-6=0
add 6 to both sides
-3x=6
divide -3 to both sides
x=-2
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7x²+3y²-28x-12y=-19
grigory [225]
Complete the square for x and y.

7x^2 + 3y^2 - 28x - 12y = -19

7x^2 - 28x + 3y^2 - 12y = -19

7(x^2 - 4x) + 3(y^2 - 4y) = -19

7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12

7(x - 2)^2 + 3(y - 2)^2 = 21

\dfrac{(x - 2)^2}{3} + \dfrac{(y - 2)^2}{7} = 1
4 0
3 years ago
MUSIC Randall recorded 8 songs on his most recent CD. The total length of the CD is 49 minutes. Find a unit rate to represent th
Juliette [100K]

Answer: 6.13

Step-by-step explanation:

From the question, we are informed that MUSIC Randall recorded 8 songs on his most recent CD and that the total length of the CD is 49 minutes.

The unit rate to represent the average length per song on the CD will be calculated by dividing 49 by 8. This will be:

= 49 minutes / 8

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6 0
2 years ago
Suppose f(x) = x^2 and
SpyIntel [72]

Given:

The two functions are:

f(x)=x^2

g(x)=\left(\dfrac{1}{3}x\right)^2

To find:

The statement that best compares the graph of g(x) with the graph of f(x).

Solution:

The horizontal stretch is defined as:

g(x)=f(kx)            ...(i)

If 0, the function f(x) is horizontally stretched by factor \dfrac{1}{k}.

If k>1, the function f(x) is horizontally compressed by factor \dfrac{1}{k}.

We have,

f(x)=x^2

g(x)=\left(\dfrac{1}{3}x\right)^2

Using these functions, we get

g(x)=f\left(\dfrac{1}{3}x\right)         ...(ii)

On comparing (i) and (ii), we get

k=\dfrac{1}{3}

Since 0, the function f(x) is horizontally stretched by factor \dfrac{1}{\frac{1}{3}}=3.

Hence, the correct option is D.

5 0
3 years ago
Necesito saber el procedimiento
Jobisdone [24]
El procedimiento es
C
5 0
3 years ago
Find the perimeter of the figure.
olga_2 [115]

Answer: My teacher told me to use 180 and divide something.

Step-by-step explanation:

6 0
2 years ago
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