Answer:
The answer is that adult tickets cost $44.50 and child tickets cost $19.
Step-by-step explanation:
Let c = the cost of child tickets and a = the cost of adult tickets.
The total amount is equal to the number of adult tickets time the cost of adult tickets plus the number of child tickets times the cost of child tickets. Set up two equations:
2a + 4c = 165
4a + 3c = 235
Solve the top equation for a:
2a + 4c = 165
2a = 165 - 4c
a = 165/2 - 4c/2
a = 82.5 - 2c
Substitute into the second equation:
4a + 3c = 235
4(82.5 - 2c) + 3c = 235
330 - 8c + 3c = 235
-5c = -95
c = -95 / -5 = 19, so child ticket cost $19.
Solve for a:
a = 82.50 - 2c
a = 82.50 - 2(19)
a = 82.50 - 38
a = $44.50, so adult tickets cost $44.50.
Proof using the first equation for the Johnson family:
2a + 4c = 165
2(44.50) + 4(19) = 165
89 + 76 = 165
165 = 165
Proof using the second equation for the Robison family:
4a + 3c = 235
4(44.50) + 3(19) = 235
178 + 57 = 235
235 = 235
divide cost by quantity. The lowest rate is the best buy:
26/8 = 3.25 each
30/5 = 6.00 each
15/4 = 3.75 each
39/12 = 3.25 each
45/10 = 4.50 each
The 8 for 26 and the 12 for 39 are both the same price each and are the better buys.
I graphed the points and I observed that it can form a right triangle. The distance required is the hypotenuse of the right triangle.
long leg is from -2 to 6 value of the x line. Its measure is 8.
short leg is form 0 to 5 value of the y line. Its measure is 5.
We will use the Pythagorean theorem to get the hypotenuse or distance of two points.
a² + b² = c²
8² + 5² = c²
64 + 25 = c²
89 = c²
√89 = √c²
9.43 = c
The distance of the two points, M and H, is 9.43
Answer:
156
Step-by-step explanation:
48*39=1872
1872 / 12=156
The answer is 1/6 or 2/6. it depends on how many yellow colored beads there are in the box.