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3 years ago

11

Evaluate 0 × |-6|. ......

1 answer:

kupik [55]3 years ago

6 0

Answer:

0

Step-by-step explanation:

Any value multiplied by zero equals zero , thus

0 × | - 6 | = 0

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Derive this with respect to x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B%281%20%2B%20%20secx%29%20%7D%20" id="Tex

Elenna [48]

$~~~~\dfrac{d}{dx} \left(\dfrac{3}{1 + \sec x} \right)\\\\\\=3 \dfrac{d}{dx} \left( \dfrac 1{ 1+ \sec x} \right)\\\\\\=3 \dfrac{d}{dx} (1+ \sec x)^{-1}\\\\\\=3 (-1) (1 + \sec x )^{-1 -1} \dfrac{d}{dx}( 1 + \sec x)\\\\\\=-3(1 + \sec x)^{-2} ( 0 + \sec x \tan x)\\\\\\=-\dfrac{3\sec x \tan x}{(1 + \sec x)^2}$

8 0

1 year ago

The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18

Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

$\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96$

So, 95% confidence interval becomes,

$(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)$

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0

3 years ago

Please can anyone help me answer this question I'm really struggling with it

Anika [276]

Answer:

$v = {210cm}^{3}$

Step-by-step explanation:

Formula for finding the volume of a triangular prism is given as:

$v = \frac{1}{2} \times b \times h \times l$

where,

b = breadth = 7cm

h = height = 6cm

l = length = 10cm

Thus,

$v = \frac{1}{2} \times 7cm \times 6cm \times 10cm$

$v = \frac{1}{2} \times 420 {cm}^{3}$

$v = \frac{ {420cm}^{3} }{2}$

$v = {210cm}^{3}$

7 0

3 years ago

HELPPP ME PLZZZZZZZZZZZZZZZZZZZZ

steposvetlana [31]

<span>m, because triangle ABC is similar to triangle EDC (by 3 congruent angles).</span>

6 0

3 years ago

Read 2 more answers

Determine the coordinates of the point on the unit circle corresponding to the given central angle. If necessary round your resu

Olenka [21]

Answer:

Option A. (-1, 0)

Step-by-step explanation:

In the figure attached,

Circle O is a unit circle (having radius r = 1 unit)

If a point A with central angles = θ, is lying on the circle then the coordinates of the point A will be,

x = r.cosθ

x = 1.cosθ = cosθ

and y = r.sinθ

y = 1.sinθ = sinθ

Therefore, coordinates representing the point A will be (cosθ, sinθ).

As per question the given point A is lying at P (a point having central angle θ = 180°)

Coordinates of point P will be

(x', y') → (cos180°, sin180°)

→ (-1, 0)

Therefore, Option A will be the answer.

3 0

3 years ago