Question

John needs to divide the sample in half once the number of bacteria has reached 1000. How many hours after the initial time must be divide the sample?

Answer 1

Answer:

Option A

Step-by-step explanation:

The complete question is attached here

The rate of increase of bacterial population  be K

As we know

$Y = Y_0 * e^{kT}$

where Y is the final population. In this case it is 1000

K is the rate of increase of population i.e 3 times per hour

T is the time in hours

Y0 is the initial population = 5

Substituting the given values, we get -

$1000 = 5 *e^{3*T}\\200 = e^{3*T}$

Taking log on both sides, we get -

ln $200$ = ln $e^{3T}$

$2.718 * 2.301 = 3T$

T = 2.084 hours

hence, option A is correct