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BlackZzzverrR [31]
4 years ago
9

How do I solve this? And how do I know what to do?

Mathematics
1 answer:
Vaselesa [24]4 years ago
3 0
I know for sure A is true. How to solve: f(-3) basically means, what is the output value when x=-3? In this case, when x=-3, the output is indeed, 2.
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-1/3x-4/3y=-2 1/3x-2/3y=4 using elimination
Minchanka [31]

-1/3x-4/3y=2

1/3x-2/3y=4

First realize that the coefficient of x is -1/3 and 1/3 which can be eliminated with addition

Adding the two equations together gets

-6/3y=6

Simplify

-2y=6

y=-3

Substitute back into original equation

1/3x-2/3(-3)=4

1/3x+2=4

1/3x=2

x=6

Answer

x=6, y=-3

Check answer

-1/3(6)-4/3(-3) =?= 2

                -2+4=2

                     2=2

Done!

5 0
2 years ago
Does anybody know how to do Factor with distribution property (Variables) ?
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Hope i was able to help

3 0
3 years ago
Read 2 more answers
SECTION B
lapo4ka [179]

Answer: The median value of data set B is -5.5, which is less than the median value of 3.1 in dataset A.

Step-by-step explanation:

Order the dataset from least to greatest:

-38 → -13 → -9 → -2 → 14 → 28

Then find the values that lies in the middle:

-38 → -13 → <u>-9 → -2</u> → 14 → 28

Since there are 2 values, find the average of those 2 values:

\frac{-9+(-2)}{2} =\frac{-11}{2} =-5.5

The median value = -5.5.

The median value of data set B is -5.5, which is less than the median value of  3.1 in dataset A.

3 0
3 years ago
Find the area of this figure<br> 28 cm<br> 23.7 cm<br> 8 cm<br> 5.7 cm
maks197457 [2]
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3 0
3 years ago
Read 2 more answers
What is the angle measure of an arc bounding sector with an area of 5pie square miles?
Snowcat [4.5K]

if the diameter is 20, the its radius must be half that or 10.

\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}

8 0
2 years ago
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