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2 years ago

Daniel drove 750 miles from his home to Texas. If x represents the number of hours Daniel drove, which expression could be

Mathematics

2 answers:

Allushta [10]2 years ago

7 0

Answer:

750/x=

Step-by-step explanation:

Hope this helps :))

11111nata11111 [884]2 years ago

4 0

Answer:750/x

Step-by-step explanation:

speed = distance ÷ time

= 750 ÷ x

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Answer:

<u>Question 1:</u>

5 pints per hour

<u>Question 2:</u>

480 tons per day

<u>Question 3:</u>

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Step-by-step explanation:

<u>Question 1:</u>

<h2><em>In the morning;</em></h2>

A farm worker packed 3 pints of grapes every 4 minutes.

1 minute = $\frac{1}{60}$ hours

Packing rate in pints per hour = 3 pints ÷ $\frac{4}{60}$ hours = 45 pints per hour

<h2><em>In the afternoon;</em></h2>

She packed 2 pints of grapes every 3 minutes.

Packing rate in pints per hour = 2 pints ÷ $\frac{3}{60}$ hours = 40 pints per hour.

The difference between her morning and afternoon packing rates (in pints per hour) = 45 pints per hour - 40 pints per hour = 5 pints per hour

<u>Question 2:</u>

A recycling plant processes an average of $\frac{1}{3}$ tons of glass each minute.

1 hour = 60 minutes

The number of tons of glass processed in 1 hour is:

$\frac{1}{3}$ × 60 = 20 tons of glass in 1 hour.

1 day = 24 hours

Number of tons of glass processed in a day = 20 tons × 24 = 480 tons

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A vehicle uses 1 $\frac{1}{8}$ gallons of gasoline to travel 13 $\frac{1}{2}$ miles.

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Step-by-step explanation:

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Svetlanka [38]

Given

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$p(x)=\frac{250}{\sqrt{x}}-5$

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a) The revenue function.

b) The marginal revenue.

c) The marginal revenue when x=200.

d) The equation of tangent, and its derivation.

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$p(x)=\frac{250}{\sqrt{x}}-5$

a) The revenue function is given by,

$\begin{gathered} R(x)=x\cdot p(x) \\ R(x)=x\times(\frac{250}{\sqrt{x}}-5) \\ R(x)=250\sqrt{x}-5x \end{gathered}$

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$\begin{gathered} R^{\prime}(x)=\frac{d}{dx}(R(x)) \\ =\frac{d}{dx}(250\sqrt{x}-5x) \\ =250\times(\frac{1}{2}\times x^{-\frac{1}{2}})-5 \\ =\frac{125}{\sqrt{x}}-5 \end{gathered}$

c) The marginal revenue when x=200 is,

$\begin{gathered} R^{\prime}(200)=\frac{125}{\sqrt{200}}-5 \\ =\frac{125}{10\sqrt{2}}-5 \\ =8.8388-5 \\ =3.8388 \\ =3.84 \end{gathered}$

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