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melisa1 [442]
3 years ago
7

What are the answers

Mathematics
1 answer:
kozerog [31]3 years ago
8 0
You shouldnt just ask for the answers. You should explain a little more
You might be interested in
as shown in the diagram below, a building cast a 72 foot shadow on the ground when the angle of elevation of the sun is 40 degre
tester [92]

Answer:

60

Step-by-step explanation:

It is just 60 I did my work lol

6 0
3 years ago
A flagpole is 12 feet tall. Its shadow is 14 ft long. How far is it from the top of the
Kisachek [45]

Answer:

Step-by-step explanation:

AC = length of flagpole = 12 ft

AB = length of shadow = 14 ft

BC = length from the top of the flagpole to the end of the shadow = x ft

Use Pythagorean theorem to find the length of x,

x² = AC² + BC²

   = 12² + 14²

  = 144 + 196

  = 340

x = √340

x = 18.4 ft

3 0
2 years ago
A motor vehicle has a maximum efficiency of 39 mpg at a cruising speed of 40 mph. The efficiency drops at a rate of 0.1 mpg/mph
svp [43]

Answer:

38 mpg

Step-by-step explanation:

Initial efficiency = 39 mpg

Initial speed = 40 mph

Final speed = 50 mph

The efficiency drop  between 40 mph and 50 mph is given by:

E_d = 0.1 \frac{mpg}{mph}*\Delta V

The total efficiency drop from 40 to 50 mph is:

E_d = 0.1 \frac{mpg}{mph}*(50-40)mph\\E_d = 1\ mpg

Therefore, the efficiency at 50 mph is:

E_{50} = E_{40} -E_d\\E_{50} = 39 -1\\E_{50} = 38\ mpg

5 0
3 years ago
Stephanie is a very good soccer player. She can kick a soccer ball with an initial velocity of 21.3 m/sec. The function that rep
algol [13]
If the ball hit the ground it means that its height is equal to 0. In order to find the time after the ball <span>will hit the ground, we need to find the solution of the equation h(x)=0 which is different to 0.

-4.9x^2+21.3x=0
x(-4.9x+21.3)=0
-4.9x+21.3=0
x=21.3/4.9 = 4.3469 seconds</span>
4 0
2 years ago
Help please with this question
choli [55]

Answer:

They lose about 2.79% in purchasing power.

Step-by-step explanation:

Whenever you're dealing with purchasing power and inflation, you need to carefully define what the reference is for any changes you might be talking about. Here, we take <em>purchasing power at the beginning of the year</em> as the reference. Since we don't know when the 6% year occurred relative to the year in which the saving balance was $200,000, we choose to deal primarily with percentages, rather than dollar amounts.

Each day, the account value is multiplied by (1 + 0.03/365), so at the end of the year the value is multiplied by about

... (1 +0.03/365)^365 ≈ 1.03045326

Something that had a cost of 1 at the beginning of the year will have a cost of 1.06 at the end of the year. A savings account value of 1 at the beginning of the year would purchase one whole item. At the end of the year, the value of the savings account will purchase ...

... 1.03045326 / 1.06 ≈ 0.9721 . . . items

That is, the loss of purchasing power is about ...

... 1 - 0.9721 = 2.79%

_____

If the account value is $200,000 at the beginning of the year in question, then the purchasing power <em>normalized to what it was at the beginning of the year</em> is now $194,425.14, about $5,574.85 less.

7 0
3 years ago
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