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Vika [28.1K]
3 years ago
10

Find the measure of an angle between 0 and 360 coterminal with 510

Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

150 degrees

Step-by-step explanation:

HOPE THIS HELPED!

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Simplify <img src="https://tex.z-dn.net/?f=%28r%5Cfrac%7B1%7D%7B2%7D4" id="TexFormula1" title="(r\frac{1}{2}4" alt="(r\frac{1}{2
Katena32 [7]

Hello!!

════ ⋆★⋆ ════

\mathbb{A~N~S~W~E~R~:}

= r · 2

➡ \Huge \sf \mathbb \color{}\underline{\colorbox{ANSWER~WITH~EXPLANATION ~!}{}}

\mathfrak{apply~the~fraction~rule:  }   a \frac{b}{c} =\frac{a~. ~b }{c}

\mathfrak{apply~rule:  }  a · 1 = a

r · 1 · 4 = r · 4

=\frac{r~.~4}{2}

\mathfrak{divide~the~numbers~:  } \frac{4}{2} = 2

= r · 2

So, your answer will be is :

= r · 2

\color{}{Hope\:it\:helps. ..}

#LearnWithBrainly

\mathbb{A~N~S~W~E~R~:}

\mathfrak{Jace}

4 0
3 years ago
PLEASE HELP I need the answer for this ASAP pleaseeeee
True [87]

Answer:

13

Step-by-step explanation:

f(x) = 5 \sqrt{x}  + 8 \\ f(1) = 5 \sqrt{1}  + 8 \\13

Hope this helps..

3 0
3 years ago
299,792,458 rounded to the greatest place value
andrew11 [14]

Answer:

300,000,000

Step-by-step explanation:

299,792,458

2 rounded to 9 is the answer

4 0
3 years ago
Read 2 more answers
Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
Ugo [173]

Answer:

Side\ B = 6.0

\alpha = 56.3

\theta = 93.7

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with \alpha, \beta, \theta

[See Attachment for Triangle]

A = 10cm

C = 12cm

\beta = 30

What the question is to calculate the third length (Side B) and the other 2 angles (\alpha\ and\ \theta)

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

B^2 = A^2 + C^2 - 2ABCos\beta

Substitute: A = 10,  C =12; \beta = 30

B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30

B^2 = 100 + 144 - 240*0.86602540378

B^2 = 100 + 144 - 207.846096907

B^2 = 36.153903093

Take Square root of both sides

\sqrt{B^2} = \sqrt{36.153903093}

B = \sqrt{36.153903093}

B = 6.0128115797

B = 6.0 <em>(Approximated)</em>

Calculating Angle \alpha

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute: A = 10,  C =12; B = 6

10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 180 - 144 *Cos\alpha

Subtract 180 from both sides

100 - 180 = 180 - 180 - 144 *Cos\alpha

-80 = - 144 *Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}

\frac{-80}{-144} = Cos\alpha

0.5555556 = Cos\alpha

Take arccos of both sides

Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)

Cos^{-1}(0.5555556) = \alpha

56.25098078 = \alpha

\alpha = 56.3 <em>(Approximated)</em>

Calculating \theta

Sum of angles in a triangle = 180

Hence;

\alpha + \beta + \theta = 180

30 + 56.3 + \theta = 180

86.3 + \theta = 180

Make \theta the subject of formula

\theta = 180 - 86.3

\theta = 93.7

5 0
3 years ago
Find the volume of a cube if each side is 3.3 inches long. Do not round your answer.
ser-zykov [4K]

35.937 inches cubed

To find volume: <em> length </em><em>x</em><em> width </em><em>x</em><em> height</em>

If the answer is right please consider marking branliest

8 0
3 years ago
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