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3 years ago

11

Lucy knows his friend was born in March but doesn't know what day! What is the likelihood that Lucy's friend will be born on Mar

ch 15th? (March has 31 days)

1 answer:

Elden [556K]3 years ago

8 0

The likelihood would be 1/31. March 15th is only one day in a 31 day period.

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This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out

Dmitry [639]

Base be y

ATQ

$\\ \sf\longmapsto xy=6050\dots 1$

$\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2$

Now

$\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy$

$\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2$

$\\ \sf\longmapsto 12100-12100=x^2+y^2$

$\\ \sf\longmapsto x^2+y^2=0\dots(3)$

From all equations

$\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy$

$\\ \sf\longmapsto (x-y)^2=0-2(6050)$

$\\ \sf\longmapsto (x-y)^2=-12100$

$\\ \sf\longmapsto (x-y)=110\dots(4)$

Now

Adding 3 and 4

$\\ \sf\longmapsto 2x=220$

$\\ \sf\longmapsto x=110m$

One side won't be covered hence

y=2(110)=220m

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2 years ago

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2 years ago

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Correct me if I’m wrong but I believe it to b

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Suppose that a box of 86 circuits is sent to a manufacturing plant. Of the 86 circuits shipped, 5 are defective. The plant manag

Triss [41]

Answer:

the probability that the shipment is accepted is 0.8865

Step-by-step explanation:

Given the data in the question;

N = 86, n/d = 5 and n = 2

now, without replacement

the probability that the shipment is accepted will be;

probability that the shipment is accepted = probability that non is defectives

so p( non is defective ) = ( (86-5)/86) × ((86-5-1)/(86-1))

p( non is defective ) = ( 81 / 86) × (80/85)

p( non is defective ) = 0.8865

Therefore, the probability that the shipment is accepted is 0.8865

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2 years ago

Solve for x. 2 1/2x−3/4(2x+5)=3/8<br><br> Please hurry

Fofino [41]

Answer:

x= - 1.48 or 0.48

Step-by-step explanation:

I used general formula. Hope I'm on a right path.

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2 years ago