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dedylja [7]
4 years ago
8

Suppose that there are nine students in a discrete mathematics class at a small college. a) Show that the class must have at lea

st five male students or at least five female students. b) Show that the class must have at least three male students or at least seven female students.
Mathematics
1 answer:
schepotkina [342]4 years ago
8 0

Answer:

a)There are genders,males and females,so at least(9/2=5) representatives of each gender.

b) If the less than 3 male students then there are more than 6 female students and if the class has less than seven female students than there are more than 2 male students.

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Please answer this correctly
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Answer:

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Answer to the question
natta225 [31]

Answer:

Value of x = -1 and y = -4

Step-by-step explanation:

BC = 3 (given)

BC = AD ( opposite sides of a parallelogram are equal)

∴ AD = 3

AD = x - y (given)

∴ 3 = x - y

3 + y = x -------- (1)

CD = 2 (given)

CD = AB (opposite sides of a parallelogram are equal)

∴ AB = 2

AB = 2x - y (given)

∴ 2 = 2x - y ----------- (2)

Putting the value of x in (1) To (2)

2 = 2(3+y) - y

2 = 6 + 2y - y

2 = 6 + y

2 - 6 = y

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Now, substitute the value of y in (1)

x = 3 + y

x = 3 + (-4)

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Therefore, the value of x = -1 and y = -4.

<u>Cross-checking</u>

2x - y = 2

2*-1 - (-4) = 2

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2 = 2

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-1+4 = 3

3 = 3

LHS = RHS

Thus verified

Hope u understand

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Thank You

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