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Ipatiy [6.2K]
3 years ago
6

How many quarts are in a gallon? Thanks !

Mathematics
2 answers:
bonufazy [111]3 years ago
6 0
4 would be your answer hope I helped :)
larisa [96]3 years ago
4 0

Answer:

4

Step-by-step explanation:

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Given that 7^2 = 12^x, evaluate 12^2x.
Elanso [62]

Answer:

12^2x = 7^4 = 2401

7^2=12^x

We know that a^x * a^x = a^(x+x) or a^2x

Multiply each side by 12^x

7^2 * 12^x=12^x * 12^x

7^2 * 12^x = 12^(x+x)

Replace 12^x with 7^2 on the left hand side since they are equal

7^2 * 7^2 = 12^ (2x)

7^(2+2) = 12^(2x)

7^4 = 12^2x

2401 = 12^2x

Step-by-step explanation:

3 0
2 years ago
What is the volume of the cylinder below?<br> 3
asambeis [7]
You need to add a picture
7 0
3 years ago
Read 2 more answers
You can transfer money from one account to another account within the same bank.
777dan777 [17]

Answer:

true

Step-by-step explanation:

many banks allow free bank-to-bank transfers if you're sending to another account that you own. you will just need to link the two accounts. you can usually do this through your bank's online banking platform.

7 0
4 years ago
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Decide if the situation involves a permutation... anyone?
ehidna [41]

Each medal is different and is handed out depending on the outcome of the race/order of the racers, so we're counting the number of permutations. 4 medals are given to 4 runners, so there are

4!=4\cdot3\cdot2\cdot1=24

possible ways to do it.

4 0
3 years ago
You are an electrician on the job. It is decided that the speed of a large DC motor is to be reduced by connecting a resistor in
olchik [2.2K]

The equivalent resistance of a series circuit is found by finding the sum of the individual resistances

The series resistor required is <u>1.25 Ω</u>

The power rating of the resistor, is <u>2,000 W</u>

The reason why the above values are correct are as follows;

The given parameter are;

Applied DC Voltage, V = 250 V

The full load armature current, I = 50 A

Required reduced armature current, I_r = 40 A

Solution:

First part

The resistance, <em>R</em>, of the circuit, is given as follows;

R = \dfrac{V}{I}

Therefore;

R = \dfrac{250 \, V}{50 \, A} = 5 \, \Omega

The voltage, V = I·R, therefore, with a series resistor, R_s, we can have;

V = I·R = I_r·(R_s + R) (given that the same current flows through both resistor)

Where the required current is I_r = 40 A, we get;

R_s = \dfrac{I \cdot R}{I_r}  - R

Which gives;

R_s = \dfrac{50  \times 5}{40}  - 5 = 1.25

The required series resistor, R_s = <u>1.25 Ω</u>

Second part;

Power, P = I²·R

The power rating of the resistor, which is added to the circuit to regulate the current to 40A is therefore, given as follows;

P_r = I_r²·R_s

∴ P_r = 40² × 1.25 = 2,000

The power rating of the resistor is <u>2,000 W</u>

<u />

Learn more about series circuit here:

brainly.com/question/9368192

6 0
2 years ago
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