<span>A) How many cups of flour are there per serving?
</span>1 ½ cups of flour --------<span>6 servings
? cups of flour ------- 1 serving
</span>1 ½
------------
6
= 3/2 x 1/6
= 1/4
answer: 1/4 cups of flour per serving
<span>B) how many total cups of sugar(white and brown) are there per serving?
</span>total white and brown: <span>2/3 + 1/3 = 3/3 = 1 cups (combine)
1 cup of sugar (white and brown) </span>--------6 servings
? cups of sugar (white and brown) ------ 1 serving
1
----- = 1/6
6
answer: 1/6 cups of sugar (white and brown) per serving
<span> (c) Suppose you modify the recipe so that it makes 9 servings. How much more flour do you need for the modified recipe than you need for the original recipe?
</span>
3/2 cups of flour --------6 servings
? cups of flour -----------9 servings
9 * 3/2
-----------
6
= (13 1/2) / 6
= 2 1/4
2 1/4 ( 9 servings) - 1 1/2(6 servings) = 3/4 cups
answer: you need 3/4 more cups of flour
Answer:
A die has 6 numbers.
So 6 numbers them being
1, 2, 3, 4, 5, 6
There’s only one number greater then 5 which is 6.
Since its 6 numbers, a die has a 1/6 chance of getting your desired number.
So it’s a 1/6 chance.
It was would numbers 000-000-0000 through 999-999-9999. So that would be 9,999,999,999 + 1 = 10 billion different 10-digit phone numbers.
Exponential function is characterized by an exponential increase or decrease of the value from one data point to the next by some constant. When you graph an exponential function, it would start by having a very steep slope. As time goes on, the slope decreases until it levels off. The general from of this equation is: y = A×b^x, where A is the initial data point at the start of an event, like an experiment. The term 'b' is the constant of exponential change. This is raised to the power of x, which represents the independent variable, usually time.
So, the hint for you to find is the term 500 right before the term with an exponent. For example, the function would be: y = 500(1.8)^x.
Answer:
Step-by-step explanation:
The logistic function of population growth, that is, the solution of the differential equation is as follows:
We use this equation to find the value of r.
In this problem, we have that:
So we find the value of r.
Applying ln to both sides of the equality
So
The differential equation is
