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lbvjy [14]
3 years ago
15

AJ graphs the function f(x)=-(x+2)^(2)-1

Mathematics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

Part 1: AJ reflected over x-axis.

Part 2: (0,-5)  and (-1,-2)

AJ plotted the graph using the function  f(x)=(x+2)^{2}-1 . This resulted the graph to reflect over x-axis

Step-by-step explanation:

Part 1: AJ mistakenly plotted over x-axis, which means he reflected the graph over x-axis.The x-value remains the same. Only the y-values are transformed into its opposite sign.

Part 2:  

Step 1: Plotting any two values for the function f(x)=-(x+2)^{2}-1

Substituting x=0, we get,

\begin{aligned}y=f(0) &=-(0+2)^{2}-1 \\=&-(2)^{2}-1 \\=&-4-1=-5 \\& y=-5\end{aligned}

Substituting x=-1, we get,

\begin{aligned}y=f(-1) &=-(-1+2)^{2}-1 \\=&-(1)^{2}-1 \\=&-1-1=-2 \\& y=-2\end{aligned}

The two x-values for AJ’s function is (0,-5)  and (-1,-2)

Step 2:

AJ plotted the graph using the function f(x)=(x+2)^{2}-1 . This resulted the graph to reflect over x-axis.

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