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Mila [183]
3 years ago
9

Which of these actions can the Consumer Product Safety Commission take

Biology
1 answer:
aniked [119]3 years ago
8 0

Answer:

C. Recall an unsafe product

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For three traits inherited in a dominant/recessive pattern, what is the probability of an offspring in a trihybrid cross between
AleksandrR [38]

Answer: For three traits inherited in a dominant/recessive pattern, the probability of an offspring in a trihybrid cross between parents heterozygous for all three traits to be recessive at exactly two of the three loci is 23/64.

Explanation: Let A, B and C represent the dominant alleles and a, b and c represent the recessive alleles. The genotype of each of the parent will be AaBbCc since it has been said to be heterozygous for all the three traits. There are eight (8) possible different types of gametes from each of the genotype. This can be calculated using 2^n where n is the number of heterozygous loci.

The number of heterozygous loci in the genotype AaBbCc is three (3). 2^3 = 8. The gametes are;

ABC

ABc

AbC

Abc

aBC

aBc

abC and

abc.

Therefore, sixty-four possible offsprings are expected from the cross AaBbCc x AaBbCc.

Out of these offsprings, twenty-three (23) are expected to be heterozygous at two loci as boldly shown in the attached image.

8 0
3 years ago
Community ecologists study the factors that determine the abundance of different species. The Abundance of three algae species (
Tema [17]

Answer:

Explanation:

Given that:

The abundance of three algal species in Lake A is now represented by the vectors:

[97, 84, 43] and [100, 80, 50]

Now if we look at Lake A, the change occurring in the vector of algae species can be determined as:

a = [100 -97, 80 - 84. 50 - 43]

a = [3, -4, 7]

Thus, the magnitude of that change is:

|a| = \sqrt{(3)^2 +(-4)^2+(7)^2}

|a| = \sqrt{9+16+49}

|a| = \sqrt{74}

|a| =8.6 \ mg/mL

The abundance of three algal species in Lake B is now represented by the vectors:

[25, 59, 22] and [20, 63, 15]

At Lake B, the change occurring in the vector of algae species can be determined as:

b = [20 -23, 63 - 59. 15 - 22]

b = [-3, -4, -7]

Thus, the magnitude of that change is:

|b| = \sqrt{(-3)^2 +(4)^2+(-7)^2}

|b| = \sqrt{9+16+49}

|b| = \sqrt{74}

|b| =8.6 \ mg/mL

Hence, for both Lake A and B, the magnitude of change is the same.

7 0
2 years ago
A plastic rod becomes negatively charged when it is rubbed with a piece of wool. how does the rob become charged?
gavmur [86]
Electrons are being transferred to the rod therefore giving a negative charge
3 0
3 years ago
Drag each tile to the correct location on the table. Not all tiles will be used.
pantera1 [17]

Answer:

Sialon/ACM112760324 can be provided in Alfa Chemistry. We are dedicated to provide our customers the best products and services.

Explanation:

https://www.alfa-chemistry.com/sialon-cas-112760-32-4-item-193752.htm

5 0
3 years ago
In hamsters, we can examine the genes for coat color and eye color which are linked:B = brown coat, b = white coat, G = green ey
Inessa [10]

Answer:

10.2 cM

Explanation:

Given,

pure breeding parent 1 : BBgg = brown coat and pink eyes

pure breeding parent 2 : bbGG = white coat and green eyes

BBGG X bbgg = F1 = BbGg ( All are brown with green eyes )

When F1 progeny is test crossed with white coat and pink eyes hamster:

BbGg X BbGg = F2 =

brown, pink eyes = 99 = parental

white, green eyes = 103 = parental

brown, green eyes = 12 = recombinant

white, pink eyes = 11 = recombinant

Recombination frequency =

(total number of recombinants / total progeny ) * 100

= [( 11 + 12 ) / ( 99 + 103 + 12 + 11 )] * 100 = (23/225)*100 = 0.102 * 100 = 10.2 %

1 % recombination frequency = 1 cM distance between genes

Hence, the distance between B and G gene is 10.2 cM

4 0
3 years ago
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