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MA_775_DIABLO [31]
3 years ago
8

Light passes through a diffraction grating with a slit spacing of 0.001 mm. A viewing screen is 100 cm behind the grating.

Physics
1 answer:
svp [43]3 years ago
3 0

Answer:

The distance from the center of the interference pattern will the first-order maximum appear is 50.38 cm.

Explanation:

Given that,

Slit space= 0.001 mm

Distance = 100 cm

Wavelength = 450 nm

We need to calculate the angle

Using formula for diffraction maxima

For first order,

d\sin\theta=m\lambda

\theta=\sin^{-1}(\dfrac{\lambda}{d})

Put the value into the formula

\theta=\sin^{-1}(\dfrac{450\times10^{-9}}{0.001\times10^{-3}})

\theta=26.74^{\circ}

We need to calculate the distance from the center of the interference pattern will the first-order maximum appear

Using formula of distance

y=D\tan\theta

Put the value into the formula

y=100\tan26.74

y=50.38\ cm

Hence, The distance from the center of the interference pattern will the first-order maximum appear is 50.38 cm.

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Answer:

C. 3.2 x 10^8 Ω•m

Explanation:

An insulator is a material that resists the flow of electricity.

In the given data the material with the highest resistivity is the best insulator

3.2 x 10^8 Ω•m

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4 years ago
How does the law of conservation of mass apply to this reaction: Al + 3HCl → H2 + AlCl3 ?
11Alexandr11 [23.1K]

Answer:

Only the hydrogen needs to be balanced. There are equal numbers of aluminum and chlorine.

Explanation:

I took the K12 test, listened to some other idiot and got it wrong, so this is the correct one.

Hope this helps!

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3 years ago
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To win the game, a placekicker must kick a football from a point 44 m (48.1184 yd) from the goal, and the ball must clear the cr
Ganezh [65]

Answer:

The distance by the ball clear the crossbar is 1.15 m

Explanation:

Given that,

Distance = 44 m

Speed = 24 m/s

Angle = 31°

Height = 3.05 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

u_{x}=u\cos\theta

Put the value into the formula

u_{x}=24\cos(31)

u_{x}=20.5\ m/s

We need to calculate the vertical velocity

Using formula of vertical velocity

u_{y}=u\sin\theta

Put the value into the formula

u_{y}=24\sin(31)

u_{y}=12.3\ m/s

We need to calculate the time

Using formula of time

t=\dfrac{d}{u_{x}}

Put the value into the formula

t=\dfrac{44}{20.5}

t=2.1\ sec

We need to calculate the vertical height

Using equation of motion

h=u_{y}t+\dfrac{1}{2}at^2

Put the value into the formula

h=12.3\times2.1-\dfrac{1}{2}\times9.8\times(2.1)^2

h=4.2\ m

We need to calculate the distance by the ball clear the crossbar

Using formula for vertical distance

d=h-3.05

Put the value of h

d=4.2-3.05

d=1.15\ m

Hence, The distance by the ball clear the crossbar is 1.15 m

7 0
4 years ago
How much force is needed to accelerate a 1000-kg car at a rate of 3 m/s squared
Burka [1]

Answer:

3000 newton force is required

Explanation:

F = ma

F= 1000 kgs x 3 m/s^ 2

F=3000(kgs x m/s^2)

F=3000 newton

8 0
3 years ago
An octopus propels itself through the water by ejecting water through a funnel in its body. How does this demonstrate Newton’s t
valina [46]

Answer: The answer would be C. When Octopus eject the water out, the water acts with an equal force on the octopus in opposite direction.

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Hope this helps! :D

8 0
3 years ago
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