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photoshop1234 [79]
4 years ago
11

An object is falling downward at a rate of 25 m/s. Two seconds later, what is its acceleration?

Physics
1 answer:
zhenek [66]4 years ago
6 0

acceleration times time falling

25*2

50 m*s^-1

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A particle is released as part of an experiment. Its speed t seconds after release is given by v (t )equalsnegative 0.4 t square
torisob [31]

Answer:

a) 2.933 m

b) 4.534 m

Explanation:

We're given the equation

v(t) = -0.4t² + 2t

If we're to find the distance, then we'd have to integrate the velocity, since integration of velocity gives distance, just as differentiation of distance gives velocity.

See attachment for the calculations

The conclusion of the attachment will be

7.467 - 2.933 and that is 4.534 m

Thus, The distance it travels in the second 2 sec is 4.534 m

6 0
3 years ago
A rocket moves upward, starting from rest with an acceleration of 29.4 m/s^2 for 3.98 s. it runs out of fuel at the end of 3.98
ValentinkaMS [17]
The distance d₁ it rises from rest while the engine is burning is given by
d₁ = d₀ + v₀t + (1/2)at²
d₁ = 0 + 0 + (1/2)·(29.4 m/s²)·(3.98 s)² = 232.85 m
So it gets to 232.85 m and then runs out of fuel.  Its velocity v₁ at this point is given by
v₁ = v₀ + at = (29.4 m/s²)·(3.98 s) = 117 m/s
At this point, gravity begins to slow it down until it reaches its peak where its velocity v₂ is zero.
v₂² = v₁² + 2ad₂
where d₂ is the distance it rises until v=0
Since gravity is decelerating the rocket, a = -g, and we have
0² = (117 m/s)² + 2(-9.8 m/s²)d₂
0 = (117)² - (19.6)·d₂
0 = 13,689 - (19.6)·d₂
d₂ = 13,689/19.6 = 698.42 m
So the total height it rises is given by
d₁ + d₂ = 232.85 m + 698.42 m
= 931.27 m





5 0
4 years ago
a thundercloud whose base is 500m above the ground. The potential difference between the base of the cloud and the m ground is 2
kolezko [41]

Answer:

1.6×10⁻⁶ N.

Explanation:

From the question,

F = (V/r)q......................... Equation 1

Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.

Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.

Substitute these values into equation 1

F = [(200×10⁶ )/500]×4.0×10⁻¹²

F = 1.6×10⁻⁶ N.

3 0
3 years ago
Come up with an example of classical conditioning in your own life or in the real world. Be sure to identify the unconditioned s
mote1985 [20]

Answer:   All learning occurs through interactions with the environment; The environment ... In the before conditioning phase, an unconditioned stimulus is paired with an ... In our example, the conditioned response would be feeling hungry when you heard ... reinforce the salivation response to make sure the behavior is well learned.

4 0
3 years ago
When working with two-dimensional motion, choose the direction of _________________ to be a positive direction.
emmainna [20.7K]

Answer:

two dimensional to the motion means motion that takes place into different directions or coordinators at the same time the simplest motion would be an object moving liner in one dimension and example of liner movement would be car moving along a state rod and ball thrown straight from the ground

6 0
2 years ago
Read 2 more answers
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