Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N
Answer:
Part a)

Part b)

Part c)

Part d)

Part e)

Part f)

Explanation:
As we know that initial velocity of the ball is given as


Now final velocity of the system is given as

Part a)
now magnitude of initial momentum is given as



Part b)
Change in momentum is given as



Part c)
As we know that average force is defined as the rate of change in momentum
so here we have



Part d)
Magnitude of change in momentum is given as



Part e)
As we know that in 2nd case the force is same as the initial force
so we will have



Part f)
Since this is elastic collision so change in kinetic energy must be ZERO

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Aluminium is ordinarily classified as a metal. It is lustrous, malleable and ductile, and has high electrical and thermal conductivity. Like most metals, it has a close-packed crystalline structure<span> and forms a cation in aqueous solution.</span>