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2 years ago

13

800 joules of work were done with a force of 200 newtons. Over what

1 answer:

Svetach [21]2 years ago

7 0

Answer:

4m

Explanation:

800/200

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A book weighing 12 n is placed on a table. how much support force does a table exert on the book?

Alenkasestr [34]

It should be 12 N. the force of the book on the table should be the same as the force of the table on the book.

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3 years ago

Which of the following statements about sidewall markings is correct? a. The load index is given as a letter. b. The traction an

vagabundo [1.1K]

Answer: all the above options are correct.

Explanation:

In sidewall markings,the load index is given as a letter,traction and temperature ratings are based on the speed rating of the tire,the tire's recommended inflation pressure and load are indicated and the DOT code indicates when and where the tire was made.

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3 years ago

A solid sphere of weight 42.0 N rolls up an incline at an angle of 36.0°. At the bottom of the incline the center of mass of the

Alecsey [184]

Answer:

Part a)

$KE = 77.95 J$

Part b)

$L = 3.16 m$

Part c)

distance L is independent of the mass of the sphere

Explanation:

Part a)

As we know that rotational kinetic energy of the sphere is given as

$KE = \frac{1}{2}I\omega_2 + \frac{1}{2}mv^2$

so we will have

$KE = \frac{1}{2}(\frac{2}{5}mR^2)(\frac{v}{R})^2 + \frac{1}{2}mv^2$

so we will have

$KE = \frac{1}{5} mv^2 + \frac{1}{2}mv^2$

$KE = \frac{7}{10} mv^2$

$KE = \frac{7}{10}(\frac{42}{9.81})(5.10^2)$

$KE = 77.95 J$

Part b)

By mechanical energy conservation law we know that

Work done against gravity = initial kinetic energy of the sphere

So we will have

$mgLsin\theta = KE$

$\frac{42}{9.81}(9.81)L sin36 = 77.95$

$L = 3.16 m$

Part c)

by equation of energy conservation we know that

$\frac{7}{10}mv^2 = mgL sin\theta$

so here we can see that distance L is independent of the mass of the sphere

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2 years ago

What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k

Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

$\sf \: F=ma$

Where,

F is force
m is mass
a is acceleration

In our case,

F = ?
m = 2500 kg
a = 20m/s

$\tt \: F_{net} = 2500 \times 20 \\ \tt= 50000$

<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>

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2 years ago

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Which pair of elements has the most similar properties?

Vanyuwa [196]

The answer is B, because oxygen and sulfur are in the same group (group 6A)

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2 years ago