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ahrayia [7]
4 years ago
11

PLEASE HELP FOR MATH

Mathematics
1 answer:
KonstantinChe [14]4 years ago
3 0

Answer:

f(x) = 3x^2 and g(x) = x + 2

Step-by-step explanation:

Given

h(x) = 3(x+2)^2

h(x) = (fog)(x)

Required

Find possible expressions for f(x) and g(x)

h(x) = (fog)(x)

This can be rewritten as:

h(x) = f(g(x))

Recall that h(x) = 3(x+2)^2

So;

h(x) = f(g(x)) = 3(x+2)^2

f(g(x)) = 3(x+2)^2

By comparison, the expression in bracket represents g(x);

Hence;

g(x) = x + 2

Replace g(x) with x

f(x) = 3(x)^2

f(x) = 3x^2

Hence, the possible expressions of f(x) and g(x) are:

f(x) = 3x^2 and g(x) = x + 2

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PLEASE HELP ME WITH THIS! IM BEHIND
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Answer:40

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Assume that you have a large sample of radioactive atoms, arranged in a rectangular lattice. Imagine that this lattice has some
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Answer:

I dont care

Step-by-step explanation:

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3 years ago
There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors
zhuklara [117]
<h3>Answer: A) 1</h3>

=========================

Explanation:

Let's label each pair of outcomes as an ordered pair (x,y)

x = first spinner outcome

y = second spinner outcome

We have these 12 different possible combos

(1,3),   (1,4),   (1,5),   (1,6)

(2,3),  (2,4),  (2,5),  (2,6)

(3,3),  (3,4),   (3,5),  (3,6)

Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.

Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.

7 0
4 years ago
16 - 2t = t + 9 + 4t
Inga [223]

Answer:

t = 1

Step-by-step explanation:

16 - 2t = t + 9 + 4t

=> 16 - 9 = 7t

=> 7 = 7t

=> t = 1

GeniusUser

6 0
2 years ago
Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
Paladinen [302]

Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

e^{C_1} =constant

So:

y(x)=C_1*sin(x)-3a

Finally, let's evaluate the initial condition in order to find C1:

y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a

Solving for C1:

C_1=4a\sqrt{3}

Therefore:

y(x)=4a\sqrt{3}* sin(x)-3a

3 0
4 years ago
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