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Doss [256]
3 years ago
5

The value of y varies directly with x, and y = 104 when x = 13. Find y when x = 2.5. HELP PLEASE

Mathematics
2 answers:
Anastaziya [24]3 years ago
8 0

See picture for solution steps and answer.

Delvig [45]3 years ago
3 0

Answer:

Step-by-step explanation:

If a given variable varies directly with another variable, it means that an increase in the value of the given variable results in a corresponding increase in the value of the other variable. Also, a decrease in the value of the given variable results in a corresponding decrease in the value of the other variable.

If value of y varies directly with x, we would introduce a constant of variation so that the expression becomes

y = kx

When x = 13, y = 104. Substituting into the above expression, it becomes

104 = 13k

k = 104/13

k = 8

The equation becomes

y = 8x

Therefore, when x = 2.5,

y = 8 × 2.5

y = 20

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Igoryamba

Answer:

x = - 1

Step-by-step explanation:

Given

4x = x^2 - 5               Transfer 4x to the right side.

Solution

x^2 - 4x - 5 = 0          Factor

(x - 5)(x + 1)

You want the negative solution. That means that the middle sign must be plus.

x + 1 = 0                   Subtract 10 from both sides

x = - 1                       Ten on the left disappears by the subtraction process.

Is that correct?

4x = x^2 - 5

x = - 10

4*(-1) = (-1)^2 - 5

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and it does work.  

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Mrrafil [7]
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the Children's Hospital sponsors a 10k race to raise money. it receives $75 per race entry and $10,000 in donations but it must
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Answer:

There would need to be at least 1,800 entries in order for them to meet their goal.

Step-by-step explanation:

To find this, we must write an equation that helps solve it. We know that for every entry (x), we gain 75 and lose 25. We can express this as the following.

75x - 25x

Then we can add the number of donations.

75x - 25x + 10,000

Then we can set it as greater than or equal to the goal number.

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Now we solve this using the order of operations.

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4 0
3 years ago
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Answer:

(a) The mean or expected value of <em>X </em>is 2.2.

(b) The standard deviation of <em>X</em> is 1.3.

Step-by-step explanation:

Let <em>X</em> = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of <em>X</em> id provided.

The formula to compute the mean or expected value of <em>X </em>is:

\mu=E(X)=\sum x.P(X=x)

The formula to compute the standard deviation of <em>X </em>is:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}

The formula of E (X²) is:

E(X^{2})=\sum x^{2}.P(X=x)

(a)

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x.P(X=x)\\=(0\times0.06)+(1\times0.25)+(2\times0.35)+(3\times0.15)+(4\times0.13)+(5\times0.06)\\=2.22\\\approx2.2

Thus, the mean or expected value of <em>X </em>is 2.2.

(b)

Compute the value of E (X²) as follows:

E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58

Compute the standard deviation of <em>X</em> as follows:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3

Thus, the standard deviation of <em>X</em> is 1.3.

4 0
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Varvara68 [4.7K]

<u>4</u>

<u></u>

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