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AlekseyPX
3 years ago
5

D = {x|x is a whole number}

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0
D = {x|x is a whole number}
E = {4}
F = {2, 4, 6, 8}

D ∩ F = {2, 4, 6, 8}


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the Pythagorean Theorem formula to find the missing side length. You must round your answer to the nearest tenth place (e.g. 10.
Rashid [163]

Answer:

I'm assuming we're solving for the hypotenuse, which is 21.5

Step-by-step explanation:

If a^2+b^2=c^2

Then 19^2+10^2 =461

This is c^2 so we must find the square root of 461

the square root of 461 is 21.47, or 21.5 rounded to the nearest tenth

5 0
3 years ago
Hi, I'm struggling on level 2 for
andrew11 [14]

Answer:

Step-by-step explanation:

we know 100 cm are in one meter,  so,  3 meters = 300 cm

then  20/300  =  20 cm  of 3 meters  , now just reduce the fraction

20/300

= 2 / 30

= 1/15

see??

6 0
2 years ago
Island A is 150 miles from Island B. A ship captain travels 310 miles from Island A and then finds that he is off course and 200
wolverine [178]

Answer:

156.37°

Step-by-step explanation:

We solve this above question, using Cosine rule which is given as:

Cos C = a² + b² - c²/2ab

Let the Angle be represented as: x

Cos x = 310² + 200² - 150²/2 × 310 × 200

x = arc cos [ 310² + 200² - 150²/2 × 310 × 200]

x = 23.63°

The angle, in degrees, that he must turn through to head straight for Island B is given as:

180° - 23.63°

= 156.37°

4 0
3 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
3 years ago
Pleaseee help I will give you all my points
suter [353]

Answer:

Ruben??

Step-by-step explanation:

Just a guess, If another person answers Listen to them

4 0
3 years ago
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